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3 years ago

6

After a trip to Mars, the human heart would be much stronger than it was on Earth

1 answer:

Mariulka [41]3 years ago

7 0

My answer to this question honestly is no

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A balloon is at a height of 81m and is ascending upwards with a velocity of 12m/s. A body of 2kg weight is dropped from it. If g

kap26 [50]

I know you are Indian by your question, HC Verma class 9 or 11 !!

if you got any problem, comment !!

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4 years ago

A warehouse is 1980 cm long,1050cm wide and 495cm high. What is the volume in cubic meters?

sveta [45]

Answer:

It should be 1,029.105 m³

But I think you can ignore the 105 because it essentially doesn't make a difference

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3 years ago

Read 2 more answers

Which is one property of coal that makes it ideal for use in a power plant?

photoshop1234 [79]

Answer:

It burns easily & It produces a lot of energy

Explanation:

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4 years ago

When one side of the Earth is at high tide, then the opposite side of the Earth is also at high tide.

Rudiy27

<span>It is true because the near side of the moon is attracted by the gravitational force due to the alignment of the planet in one Straight line.The opposite side is due to the movement of earth towards moon side during alignment.Soon both side, there will be high tide at the same time.</span>

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4 years ago

Estimate the acceleration due to gravity at the surface of Europa (one of the moons of Jupiter) given that its mass is 4.9×1022k

Taya2010 [7]

Answer: $g=1.97 m/s^2$

Explanation:

Given

mass of Jupiter is $M=4.9\times 10^{22} kg$

Density of Jupiter is same as Earth

$density\ of\ Earth=density\ of\ Jupiter=5510 kg/m^3$

$mass=volume\times density$

considering Jupiter to be sphere of radius r

$M=\frac{4}{3}\times \pi r^3\times \rho$

$r^3=\frac{3M}{\rho \times 4\pi}$

$r^3=\frac{3\times 4.9\times 10^{22}}{5510\times 4\pi}$

$r=(\frac{3\times 4.9\times 10^{22}}{5510\times 4\pi})^{\frac{1}{3}}$

$r=1.28\times 10^6 m$

acceleration due to gravity is given by

$g=\frac{GM}{r^2}$

$g=\frac{6.67\times 10^{-11}\times 4.9\times 10^{22}}{(1.28\times 10^6)^2}$

$g=1.97 m/s^2$

3 0

4 years ago