Ask question

Ask question

All categories

2 years ago

5

A weightlifter lifts a weight of 500 N from the ground over her head, a distance of 1.8 m. How much work has been done to move t

he weight?

1 answer:

Maksim231197 [3]2 years ago

3 0

Answer is 900N

Hope this helps c:

You might be interested in

The rebirth of science and learning during the fifteenth century is termed the

Pepsi [2]

The Renaissance, was the rebirth to science as well as many other advancements

5 0

3 years ago

The volumes of a sample of lead and a sample of platinum are the same: 2 cm3. The density of lead is 11.3 g/cm3 and the density

Vlad1618 [11]

The answer is C. The mass of the platinum sample is greater than the mass of the lead sample. As I explained in a previous answer, if they are the same volume, but one is heavier, then it must be more dense. In this particular example, the platinum is more dense than the lead, and therefore has more mass.

4 0

3 years ago

Read 2 more answers

A dog, that has a mass of 16 kgs, runs across a yard. What is the average force applied to the dog from the ground as it runs ac

VikaD [51]

Answer:

156.96 N

Explanation:

F=ma where m is the mass and a is acceleration

Substituting 16 Kg for m and 9.81 m/s2 for g then

F=16*9.81= 156.96 N

4 0

3 years ago

Imagine a 15kg block moving with a speed of 20m/s. Calculate the kinetic energy of this block. (Show the equation, show your wor

dmitriy555 [2]

Answer:

The answer to your question is: Ke = 3000 Joules

Explanation:

Data

mass = 15 kg

speed = 20 m/s

Kinetic energy = ?

Equation

$Ke = \frac{1}{2}mv^{2}$

$Ke = \frac{1}{2}(15)(20)^{2}$

Ke = 3000 Joules

5 0

3 years ago

Read 2 more answers

Question: Self-test 3.12 Calculate the change in G for ice at -10°C, with density 917 kg mº, when the pressure is increased from

Akimi4 [234]

The change in the Gibb's free energy per mole (G) is 1.96 J.

The given parameters:

Density of the ice, ρ = 917 kg/m³
Initial pressure, P₁ = 1.0 bar
Final pressure, P₂ = 2.0 bar
Temperature, T = - 10 C
Mass of water = 18 g

The change in the Gibb's free energy per mole (G) is calculated as follows;

$\Delta G = V(P_2-P_1) \\\\$

where;

V is the volume of the ice

$Density = \frac{Mass}{Volume} \\\\Volume = \frac{Mass}{Density} \\\\Volume = \frac{18 \times 10^{-3} \ kg}{917 \ m^3} \\\\Volume = 1.96 \times 10^{-5} \ m^3\\\\Volume = 1.96 \times 10^{-5} \ m^3 \times \frac{1000 \ L}{m^3} \\\\Volume = 0.0196 \ L$

Change in pressure;

$P_2 - P_1 = 2.0 \ bar \ - \ 1.0 \ bar = 1.0 \ bar = 0.987 \ atm$

The change in the Gibb's free energy per mole (G);

$\Delta G= V(P_2-P_1)\\\\\Delta G = 0.0196\ L \times 0.987\ atm \\\\\Delta G = 0.0193 \ L.atm\\\\1 \ L.atm = 101.325 \ J\\\\\Delta G = 0.0193 \ L.atm \times \frac{101.325 \ J}{1 \ L.atm} \\\\\Delta G = 1.96 \ J$

Thus, the change in the Gibb's free energy per mole (G) is 1.96 J.

Learn more about Gibb's free energy here: brainly.com/question/10012881

3 0

2 years ago