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ziro4ka [17]
3 years ago
8

A perfectly conductive plate is placed in the y z-plane. An electromagnetic wave with electric field is incident on the conducto

r. If the wave strikes the plate at t = 0, what are the directions of the electric and magnetic fields of the reflected wave immediately after reflection?
Physics
1 answer:
Marizza181 [45]3 years ago
7 0

Answer:

Electric field will move in y-direction, while magnetic field will move in z-direction.

Explanation:

If we make a sketch of electromagnetic wave propagation, we will discover that, the direction of the electric field will be towards y-direction and the direction of the magnetic field will be towards z-direction.

Therefore, if electromagnetic wave with electric field is incident on the conductor, immediately after reflection, Electric field will move in y-direction, while magnetic field will move in z-direction.

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agasfer [191]
  • Current=2.72A=I
  • Time=t=9.88s
  • Charge=Q

\\ \rm\longmapsto I=\dfrac{Q}{t}

\\ \rm\longmapsto Q=It

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A 500g cart moving at 0.25 m/s collides and sticks to a stationary 750g cart. How fast do the two carts
Tresset [83]

Answer:

0.1 m/s

Explanation:

Please see attached photo for explanation.

Mass of 1st cart (m₁) = 500 g

Initial velocity of 1st cart (u₁) = 0.25 m/s

Mass of 2nd cart (m₂) = 750 g

Initial velocity of 2nd cart (u₂) = 0 m/s

Velocity (v) after collision =.?

m₁u₁ + m₂u₂ = v(m₁ + m₂)

(500 × 0.25) + (750 × 0) = v(500 + 750)

125 + 0 = v(1250)

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v = 125 / 1250

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3 0
3 years ago
A 4-foot spring measures 8 feet long after a mass weighing 8 pounds is attached to it. The medium through which the mass moves o
aniked [119]

Correct question is;

A 4-foot spring measures 8 feet long after a mass weighing 8 pounds is attached to it. The medium through which the mass moves offers a damping force numerically equal to √2 times the instantaneous velocity. Find the equation of motion if the mass is initially released from the equilibrium position with a downward velocity of 7 ft/s. (Use g = 32 ft/s²)

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x(t) = 7te^(-2t√2)

Explanation:

We are given;

Weight; W = 8 lbs

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m = 8/32

m = ¼ slugs

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m(d²x/dt²) = -kx - β(dx/dt)

Rearranging this, we have;

(d²x/dt²) + (β/m)(dx/dt) + (k/m)x = 0

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(d²x/dt²) + (√2/(¼))(dx/dt) + (2/(¼))x = 0

>> (d²x/dt²) + (4√2)dx/dt + 8x = 0

The auxiliary equation of this is;

m² + (4√2)m + 8 = 0

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m1 = m2 = -2√2

The general solution will be gotten from;

x_t = c1•e^(mt) + c2•t•e^(mt)

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x_t = c1•e^(mt) + c2•t•e^(mt)

At initial condition of t = 0, x_t = 0 and thus; c1 = 0

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Since c1 = 0, then c2 = 7

Thus,equation of motion is;

x(t) = 7te^(-2t√2)

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