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maw [93]
3 years ago
14

Do mice show a preference for using one paw over the other? Attempting to answer this question, a researcher tested a random sam

ple of 48 mice and observed which forepaw (right or left) the mice used to retrieve food from a narrow tube. Eighteen of the mice used their right paw, while the rest used their left paw.
Does this data suggest that mice show a preference towards one paw over the other? Carry out the appropriate test and include all steps for full credit.
During the course of the experiment, the researcher noticed that individual mice sometimes switched which forepaw they used to retrieve the food. So she repeated this study on the same 48 mice, but measured each one 10 times and she recorded which forepaw was used each time. With her new dataset of 480 observations, would you be able to run the same analysis as in part (a)? If so, carry out the analysis and compare the results. If not, why not?
Mathematics
1 answer:
Stels [109]3 years ago
4 0

Answer:

It all depends on the food they are going for, just like humans, mice have instincts. For example, if you were falling forward, which foot would you put out? Most likely the opposite one. I hope this helps you!

Step-by-step explanation:

You might be interested in
At 107°F, a certain insect chirps at a rate of 92 times per minute, and at 113°F, they chirp 116 times per minute. Write an equa
dsp73

Answer:

The equation in slope-intercept form that represents the situation is y=0.25*x + 84 where y represents the temperature in ° F and x the number of chirps per minute.

Step-by-step explanation:

A linear equation can be expressed in the form y=m*x + b. In this equation, x and y are coordinates of a point, m is the slope and b is the y coordinate of the y-intercept. Since this equation describes a line in terms of its slope and its y-intercept, this equation is said to be in its slope-intercept form.

When there are two points of a line (x1, y1) and (x2, y2), the slope is determined by the quotient between the difference of the ordinate of these two points and the difference of the abscissa of the same points. This is:

m=\frac{y2-y1}{x2-x1}

Having a point on the line, you can substitute the values ​​of m, x and y in the equation y = mx + b and thus find b.

In this case:

  • (x1, y1): (92, 107)
  • (x2, y2): (116, 113)

So:

m=\frac{113-107}{116-92}

m= 0.25

substituting the values ​​of m, x1 and y1 in the equation y = mx + b you have:

107= 0.25*92 + b

107 - 0.25*92= b

84=b

<u><em>The equation in slope-intercept form that represents the situation is y=0.25*x + 84 where y represents the temperature in ° F and x the number of chirps per minute.</em></u>

3 0
3 years ago
Ans: 720cm
UkoKoshka [18]

Answer:

663

Step-by-step explanation:

the total number of students can be determined using this equation :

(total ratio of Chinese and Indian students / total ratio of students) x n = 468

total ratio of Chinese and Indian students = 4 + 8 = 12

total ratio of students 4 + 8 + 5 = 17

N = TOTAL NUMBER OF STUDENTS

12/17) x n = 468

multiply both sides of the equation by 17/12

n = 663

3 0
3 years ago
A² +6² = c²<br> Find the length of c:
yanalaym [24]
64+36=c^2
100=c^2
square root both sides for 10=c
10 is your answer
3 0
3 years ago
Read 2 more answers
Sandy spent half of Her allowance going to the movies. She washed the family car and earn seven dollars. What is your weekly all
Veseljchak [2.6K]

Answer:

I'm pretty sure it's 13.

Step-by-step explanation:

4 0
3 years ago
3x+-2y=-6<br> 5x-2y=7<br> how do i solve this Elimination pls
tatuchka [14]

Answer:

x=\frac{13}{2}, y=\frac{51}{4}

Step-by-step explanation:

We\ are\ given,\\3x-2y=-6\\5x-2y=7\\Considering\ this\ system\ of\ equations,\\Let\ 3x-2y=-6\ be\ E_1\\Let\ 5x-2y=7\ be\ E_2,\\Hence,\\Multiplying\ E2\ with\ -1, we\ get:\\3x-2y=-6\\-1(5x-2y)=7*-1\\Hence,\\3x-2y=-6\\-5x+2y=-7\\Now,\\Lets\ add\ E_1\ and\ E_2\ together\\Hence,\\(3x-2y)+(-5x+2y)=(-6)+(-7)\\Hence,\\3x-2y-5x+2y=-13\\Arranging\ And\ Adding\ Like\ terms,\ we\ have:\\3x-5x-2y+2y=-13\\Hence,\\-2x+0y=-13\\-2x=-13\\x=\frac{-13}{-2}=\frac{13}{2}

Now,\ we\ can\ substitute\ x=\frac{13}{2}\ in\ E_1\ or\ E_2,\\But,\\Here,\ we'll\ substitute\ it\ in\ E1,\\Hence,\\Substituting\ x=\frac{13}{2}\ in\ E1,\ we\ have:\\3*\frac{13}{2}-2y=-6\\\frac{39}{2}-2y=-6\\-2y=-6- \frac{39}{2}\\-2y=\frac{-12-39}{2}\\-2y=\frac{-51}{2}\\y=\frac{-51}{2*-2}=\frac{51}{4}\\Hence,\\x=\frac{13}{2}, y=\frac{51}{4}

4 0
3 years ago
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