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MrRa [10]
3 years ago
5

Roberto made a 74 on last week's math quiz. This week he made an 85 on

Mathematics
1 answer:
FinnZ [79.3K]3 years ago
6 0

Answer:

His quiz score increased by about 7%.

Step-by-step explanation:

Take the two quiz scores and add them together to get 159.

Take the difference between the two quiz scores to get 11.

Divide the difference by the sum to get 0.0692 or about 7%.

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15)
Ludmilka [50]

Answer:

A, x>3

Step-by-step explanation:

You solve the equation as normal by crossing out both sides and getting what equals to x, but since you divided by a negative the sign flips and you are left with your answer. Hope this helps!

8 0
3 years ago
7300 dollars is placed in an account with an annual interest rate of 7.75%. To the nearest tenth of a year, how long will it tak
ryzh [129]
It will take 55 years for the account value to reach 38200 dollars.
4 0
3 years ago
The probability that a professional baseball player will get a hit is 1/3. Calculate the exact probability that he will get at l
Evgesh-ka [11]
It is given here that there is 1/3 probability of professional baseball player will get a hit. Hence if  at least three hits are gained out of 5 attempts, the calculation goes:  5C3* (1/3)^3*(2/3)^2 + 5C4* (1/3)^4*(2/3)^1 +5C5 *<span>(1/3)^5*(2/3)^0 equal to 0.21. </span>
3 0
3 years ago
LCM of 4/6 and 4/8????
Svet_ta [14]

Answer:

24 is the LCM of 4,6,8. I think thats what your looking for.

Hope this helps!

Step-by-step explanation:

5 0
2 years ago
How much pure acid should be mixed with 6 gallons of a 20% acid solution in order to get a 90% acid solution?
beks73 [17]
So, how much acid is there in 6 gallons?  well is 20% acid or (20/100), so the amount of acid in it just (20/100) * 6 or 1.2, the rest is say water.

now, if we want a 90% solution, and say we add "y" gallons, how much acid is in it?  well (90/100) * y, or 0.9y.

now let's add "x" gallons of pure acid, now, pure acid is just pure acid, so is 100% acid, how much acid is there in it?  (100/100) * x, or 1x or just x.

we know whatever "x" and "y" amounts are, they -> x + 6 = y

and we also know that x + 1.2 = 0.9y

\bf \begin{array}{lccclll}&#10;&\stackrel{gallons}{acid}&\stackrel{acid~\%}{quantity}&\stackrel{acid~gallons}{quantity}\\&#10;&------&------&------\\&#10;\textit{pure acid}&x&1.00&x\\&#10;\textit{20\% sol'n}&6&0.20&1.2\\&#10;------&------&------&------\\\&#10;mixture&y&0.90&0.9y&#10;\end{array}&#10;\\\\\\&#10;\begin{cases}&#10;x+6=\boxed{y}\\&#10;x+1.2=0.9y\\&#10;----------\\&#10;x+1.2=0.9\left( \boxed{x+6} \right)&#10;\end{cases}&#10;\\\\\\&#10;x+1.2=0.9x+5.4\implies x-0.9x=5.4-1.2\implies 0.1x=4.2&#10;\\\\\\&#10;x=\cfrac{4.2}{0.1}\implies x=\stackrel{gallons}{42}
3 0
3 years ago
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