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3 years ago

Find the product. 1/8 times 8 to the square root

Mathematics

2 answers:

cupoosta [38]3 years ago

6 0

Answer:

0.35355339

Step-by-step explanation:

Nastasia [14]3 years ago

3 0

Step-by-step explanation:

The product 1/8 times 8 to the square root

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What is the value of yearly compensation package that includes $65,000 salary the forecast of a $350 Dollar per month health ins

Klio2033 [76]

Answer:

$69560

Step-by-step explanation:

The yearly compensation package includes a yearly salary of $65000, the health insurance plan of $350 per month and a life insurance premium of $30 per month.

Total compensation in health insurance plan is $(350 × 12) = $4200

Total compensation in life insurance premium is $(30 × 12) = $360

Therefore, total yearly compensation package is $(65000 + 4200 + 360) = $69560 (Answer)

4 0

3 years ago

How do you solve each system of equations?

stiv31 [10]

Answer:

$x=1,y=3,z=1$

Step-by-step explanation:

$4x-4y+4z=-4$

$4x=-4+4y-4z$

$x=-1+y-z$

Substitute $x=-1+y-z$ into second equation:

$4\left(-1+y-z\right)+y-2z=5$

$-4+4y-4z+y-2z=5$

$5y-6z-4=5$

$y=\frac{6z+9}{5}$

Substitute $x=-1+y-z$ and $y=\frac{6z+9}{5}$ into the third equation:

$\frac{-41z-54}{5}+3=-16$

$-41z-54=-95$

$z=1$

Substitute $z=1$ into $y=\frac{6z+9}{5}$ :

$y=3$

Plug in y and z values into $x=-1+y-z$ :

$x=1$

4 0

3 years ago

Please help! I don't understand how to solve this problem

Ilia_Sergeevich [38]

Using the z-distribution, a sample of 142,282 should be taken, which is not practical as it is too large of a sample.

<h3>What is a z-distribution confidence interval?</h3>

The confidence interval is:

$\overline{x} \pm z\frac{\sigma}{\sqrt{n}}$

The margin of error is:

$M = z\frac{\sigma}{\sqrt{n}}$

In which:

$\overline{x}$ is the sample mean.

z is the critical value.

n is the sample size.

$\sigma$ is the standard deviation for the population.

Assuming an uniform distribution, the standard deviation is given by:

$S = \sqrt{\frac{(4 - 0)^2}{12}} = 1.1547$

In this problem, we have a 95% confidence level, hence $\alpha = 0.95$ , z is the value of Z that has a p-value of $\frac{1+0.95}{2} = 0.975$ , so the critical value is z = 1.96.