Answer:
top one is 0.6 bottom one is 0.1
Yes 21/50 is in simplest form
Given :-
- Two triangles with their two angles equal .
To Find :-
Answer :-
Here in ∆ABC and ∆EDC ,
CAB =
CED (given )-
CBA =
CDE (given)
Therefore by AA similarity criterion , we can say that ∆ABC ~ ∆EDC . Also we know that corresponding sides of similar triangles are proportional . So ,
→ AC/EC = BC/DC
→ AC/9 = 8/12
→ AC = 8/12 * 9
→ AC = 6
<u>Hence</u><u> the</u><u> </u><u>measure</u><u> of</u><u> </u><u>side </u><u>AC </u><u>is </u><u>6</u><u> </u><u>.</u>
I hope this helps.
Hello,

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