Salty is solid molecular in water
<h3><u>Answer;</u></h3>
321.8 g CaF2
321.5 g Al2(CO3)3
<h3><u>Explanation;</u></h3>
The equation for the reaction is;
3 CaCO3 + 2 AlF3 → 3 CaF2 + Al2(CO3)3
Number of moles of CaCO3 will be;
=(412.5 g CaCO3) / (100.0875 g CaCO3/mol)
= 4.12139 mol CaCO3
Number of moles of AlF3 will be;
= (521.9 g AlF3) / ( 83.9767 g AlF3/mol)
= 6.21482 mol AlF3
But;
4.12139 moles of CaCO3 would react completely with 4.12139 x (2/3) = 2.74759 moles of AlF3.
Thus; there is more AlF3 present than that, so AlF3 is in excess, and CaCO3 is the limiting reactant.
Therefore;
Mass of CaF2 will be;
(4.12139 mol CaCO3) x (3/3) x (78.0752 g CaF2/mol) = 321.8 g CaF2
Mass of Al2(CO3)3 on the other hand will be;
(4.12139 mol CaCO3) x (1/3) x (233.9903 g Al2(CO3)3/mol) = 321.5 g Al2(CO3)3
Answer:
The fraction of the available octahedral positions are filled with 
ions is 
Explanation:
If there are n numbers of spheres in HCP in packing:
Number of octahedral void = n
Number of tetrahedral void = 2n
Total number of voids = n + 2n = 3n
The 
crystal structure consists of an HCP arrangement of 
ions.
Number of spheres in HCP = 6
Number of = 6
Number of octahedral voids = 6
Number of tetrahedral void = 12
Number of aluminum ions when there are 6 ion =
Number of voids in which 
ions are present = 4
The fraction of the available octahedral positions are filled with ions = 
