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4 years ago

When 412.5g of calcium carbonate react with 521.9g of aluminum fluoride,how many grams of each product can be produced

Chemistry

1 answer:

aliya0001 [1]4 years ago

3 0

<h3><u>Answer;</u></h3>

321.8 g CaF2

321.5 g Al2(CO3)3

<h3><u>Explanation;</u></h3>

The equation for the reaction is;

3 CaCO3 + 2 AlF3 → 3 CaF2 + Al2(CO3)3

Number of moles of CaCO3 will be;

=(412.5 g CaCO3) / (100.0875 g CaCO3/mol)

= 4.12139 mol CaCO3

Number of moles of AlF3 will be;

= (521.9 g AlF3) / ( 83.9767 g AlF3/mol)

= 6.21482 mol AlF3

But;

4.12139 moles of CaCO3 would react completely with 4.12139 x (2/3) = 2.74759 moles of AlF3.

Thus; there is more AlF3 present than that, so AlF3 is in excess, and CaCO3 is the limiting reactant.

Therefore;

Mass of CaF2 will be;

(4.12139 mol CaCO3) x (3/3) x (78.0752 g CaF2/mol) = 321.8 g CaF2

Mass of Al2(CO3)3 on the other hand will be;

(4.12139 mol CaCO3) x (1/3) x (233.9903 g Al2(CO3)3/mol) = 321.5 g Al2(CO3)3

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3 years ago

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3 years ago

A sample of gas is observed to effuse through a pourous barrier in 4.98 minutes. Under the same conditions, the same number of m

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Answer:

The molar mass of the unknown gas is $\mathbf{ 51.865 \ g/mol}$

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the same number of moles of an unknown gas requires time t₂ = 6.34 minutes to effuse through the same barrier.

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Graham's Law of Diffusion states that, at a constant temperature and pressure; the rate of diffusion of a gas is inversely proportional to the square root of its density.

i.e

$R \ \alpha \ \dfrac{1}{\sqrt{d}}$

$R = \dfrac{k}{d}$ where K = constant

If we compare the rate o diffusion of two gases;

$\dfrac{R_1}{R_2}= {\sqrt{\dfrac{d_2}{d_1}}$

Since the density of a gas d is proportional to its relative molecular mass M. Then;

$\dfrac{R_1}{R_2}= {\sqrt{\dfrac{M_2}{M_1}}$

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Thus; replacing the value of R into the above previous equation;we have:

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We can equally say:

${\dfrac{t_2}{t_1}}= {\sqrt{\dfrac{M_2}{M_1}}$

${\dfrac{6.34}{4.98}}= {\sqrt{\dfrac{M_2}{32}}$

$M_2 = 32 \times ( \dfrac{6.34}{4.98})^2$

$M_2 = 32 \times ( 1.273092369)^2$

$M_2 = 32 \times 1.62076418$

$\mathbf{M_2 = 51.865 \ g/mol}$

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3 years ago