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bagirrra123 [75]
3 years ago
15

Help needed ASAP, I will mark your answer as brainliest.

Chemistry
2 answers:
posledela3 years ago
5 0
B i think is the correct answer
evablogger [386]3 years ago
4 0

Answer:

b

Explanation:

b

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<h3><u>Answer:</u></h3>

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Vera_Pavlovna [14]
<span>A chemist adds 155.0ml of a 4.10 X 10^-5 mmol/L of a zinc oxalate (ZnC2O4)solution to a reaction flask. Calculate the mass in micrograms of zinc oxalate the chemist has added to the flask. 1mmol = 10^-3 mol Therefore 4.10*10^-5mmol = 4.10*10^-8mol molar mass ZnC2O4 = 65.39+(2*12.011)+(4*15.99) = 153.372g/mol You have 4.10*10^-8 mol/litre =153.372 * 4.10*10^-8 = 6.29*10^-6 grams / litre (* see below) But you have 155ml. Mass of ZnC2O4 = 155/1000*6.29*10^-6 g Mass is = 9.75*10^-7 grams 1µg = 10^-6 g You then have 9.75*10^-7/10^-6 = 0.975µg ZnC2O4 (*see below) at this point you could have said: 1µg = 10^-6 g therefore you have a solution of 6.29µg per litre, 155ml = 6.29*155/1000 = 0.975µg ZnC2O4</span>
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3 years ago
I’ll give 5 stars and Brainliest plus this is 20 points lol
Daniel [21]

Answer:

I think is b

Explanation:

4 0
2 years ago
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