The two electrons in a helium atom occupy

A galvanic (voltaic) cell consists of an electrode composed of chromium in a 1.0 M chromium(III) ion solution and another electr

svetlana [45]

Answer: The potential of the following electrochemical cell is 1.08 V.

Explanation:

$E^0_(Cr^{3+}/Cr)$ =-0.74V[/tex]

$E^0_(Cu^{2+}/Cu)$ =0.34V[/tex]

The element with negative reduction potential will lose electrons undergo oxidation and thus act as anode.The element with positive reduction potential will gain electrons undergo reduction and thus acts as cathode.

Here Cr undergoes oxidation by loss of electrons, thus act as anode. copper undergoes reduction by gain of electrons and thus act as cathode.

$2Cr+3Cu^{2+}\rightarrow 2Cr^{3+}+3Cu$

$E^0=E^0_{cathode}- E^0_{anode}$

Where both $E^0$ are standard reduction potentials, when concentration is 1M.

$E^0=E^0_{[Cu^{2+}/Ni]}- E^0_{[Cr^{3+}/Cr]}$

$E^0=0.34-(-0.74)=1.08V$

Thus the potential of the following electrochemical cell is 1.08 V.

6 0

3 years ago

Which statement explains how the periodic table is arranged?. . A.. The periodic table is arranged by the radioactivity levels i

vova2212 [387]

The periodic table is arranged by the outermost electrons of the elements and this is the statement among the given statements that explains how the periodic table is arranged. The correct option among all the options that are given in the question is the second option or option "B".

7 0

3 years ago

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What type of bonding occurs in a sample of pure chromium, cr? in other words, how is one chromium atom held to another chromium

spayn [35]

Chromium is a metal in nature. So when one chromium is bonded to another chromium, there is a weak intermolecular forces which helds them together which we call as “metallic bonding”.

Metallic bonding is the intermolecular force of attraction which exist between valence electrons and the metal atoms. It is considered as the sharing of various detached electrons between many positive ions, whereby the electrons serve as a "glue" which gives the substance a definite structure.

4 0

3 years ago

A piece of high-density Styrofoam measuring 24.0 cm by 36.0 cm by 5.0 cm floats when placed in a tub of water. When a 1.5 kg boo

zheka24 [161]

Explanation:

The given data is as follows.

Width of Styrofoam = 24.0 cm

Length of Styrofoam = 36.0 cm

Height of Styrofoam = 5.0 cm

Therefore, volume of the Styrofoam will be calculated as follows.

Volume = length × width × height

= (36.0 × 24.0 × 5.0) $cm^{3}$