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3 years ago

Find the hypotenuse of a right triangle that has one side of 7 cm and another one of 3 cm.

2 answers:

6 0

To find it, use the formula a^2 plus b^2=c^2. So 7 times 7 is 49, 3 times 3 is 9. 49 plus 9 is 58, take the square root of your answer which would be 7.6 because that is the square root of 58 rounded to the nearest tenth.

Over [174]3 years ago

5 0

The hypotenuse is the square root of 58.
a^2+b^2=c^2
7^2+3^2=c^2
49+9=c^2
58=c^2
c= square root of 58

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What is a simplified eCarlotta thinks that 3y + 5y3 is the same as 8y4. Which statement shows that it is NOT the same?Xpression

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Answer:

$(x + y) - (x - y) =2y$

$3y + 5y^3 \ne 8y^4$

Step-by-step explanation:

Solving (a):

Given

$(x + y) - (x - y)$

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$(x + y) - (x - y)$

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$(x + y) - (x - y) = x + y - x + y$

Collect Like Terms

$(x + y) - (x - y) = x - x+ y + y$

$(x + y) - (x - y) = y + y$

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Solving (b):

Given

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Required

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The expression that shows this is:

$3y + 5y^3 \ne 8y^4$

Take for instance; y=2

Substitute 2 for y in $3y + 5y^3 \ne 8y^4$

$3*2 + 5*2^3 \ne 8*2^4$

Evaluate all exponents

$9 + 5*8 \ne 8*16$

$9 + 40 \ne 128$

$49 \ne 128$

The above expression supports $3y + 5y^3 \ne 8y^4$

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