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3 years ago

Identify each sample as biased or unbiased and describe its type. Explain your reasoning.

Mathematics

2 answers:

tatuchka [14]3 years ago

8 0

Answer:

2. biased because they're only surveying one classroom and not more

6. unbiased because I'm assuming the manager is using a different phone every 20 minutes

8. unbiased because he they surveyed many countries

Step-by-step explanation:

hope this helps sorry if incorrect have a good rest of your night/day :) ❤

can I please get brainliest

Shkiper50 [21]3 years ago

4 0

Answer: Hope this helps when i am only in third grade but the question 6. answer is i think in each 20 minutes he gets a cell phone so 20 times 1 is 20 so he will get 20 cell phones.

I;m soooooooooooooooo sorry if this doesn't help but don't think i'm doing this for point.

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Log(5x-4)-log(×+1)=log4

Anna007 [38]

Answer:

x = 8

Step-by-step explanation:

log(5x-4)-log(x+1)=log 4

log [ (5x - 4) / (x+ 1) ] = log 4

[ log (a/b) = loga - logb]

(5x - 4 ) / ( x + 1) = 4

(5x - 4) = 4x + 4

5x - 4x = 4 + 4

x = 8

Hope it will help :)❤

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3 years ago

A dilation with a scale factor of 4 and centered at the origin is applied to AB with endpoints A(1,3) and B(5,3) drag and drop t

Vadim26 [7]

A'= (4,12)
B'=(20,12)

7 0

3 years ago

Read 2 more answers

AreA of a circle pls help

Oksi-84 [34.3K]

Answer:

28.26 $in^{2}$

Step-by-step explanation:

Given,

Radius of the circle = 3in.

Area = ?

They have told us to use 3.14 for $\pi$

Area formula = $\pi r^{2}$

=> 3.14 * 3 * 3

=> 3.14 * 9

=> 28.26 $in^{2}$

Therefore the area of the circle is 28.26 $in^{2}$

Hope it helps :)

4 0

3 years ago

Read 2 more answers

Which expression below is equivalent to 2x + 8?

mash [69]

Answer: D) x+4+x+4

The two x terms combine to x+x = 2x

The other pair of like terms, the constants, add to 4+4 = 8

Overall we get 2x+8

2x+8 is also equivalent to 2(x+4) when you factor out the GCF 2.

7 0

3 years ago

Factor the polynomial, x2 + 5x + 6

patriot [66]

Answer:

Choice b.

$x^{2} + 5\, x + 6 = (x + 3)\, (x + 2)$ .

Step-by-step explanation:

The highest power of the variable $x$ in this polynomial is $2$ . In other words, this polynomial is quadratic.

It is thus possible to apply the quadratic formula to find the "roots" of this polynomial. (A root of a polynomial is a value of the variable that would set the polynomial to $0$ .)

After finding these roots, it would be possible to factorize this polynomial using the Factor Theorem.

Apply the quadratic formula to find the two roots that would set this quadratic polynomial to $0$ . The discriminant of this polynomial is $(5^{2} - 4 \times 1 \times 6) = 1$ .

$\begin{aligned}x_{1} &= \frac{-5 + \sqrt{1}}{2\times 1} \\ &= \frac{-5 + 1}{2} \\ &= -2\end{aligned}$ .

Similarly:

$\begin{aligned}x_{2} &= \frac{-5 - \sqrt{1}}{2\times 1} \\ &= \frac{-5 - 1}{2} \\ &= -3\end{aligned}$ .

By the Factor Theorem, if $x = x_{0}$ is a root of a polynomial, then $(x - x_0)$ would be a factor of that polynomial. Note the minus sign between $x$ and $x_{0}$ .

The root $x = -2$ corresponds to the factor $(x - (-2))$ , which simplifies to $(x + 2)$ .
The root $x = -3$ corresponds to the factor $(x - (-3))$ , which simplifies to $(x + 3)$ .

Verify that $(x + 2)\, (x + 3)$ indeed expands to the original polynomial:

$\begin{aligned}& (x + 2)\, (x + 3) \\ =\; & x^{2} + 2\, x + 3\, x + 6 \\ =\; & x^{2} + 5\, x + 6\end{aligned}$ .

4 0

3 years ago