All categories

2 years ago

What is the hybridization and shape for an XeF6 2+ molecule?

Chemistry

1 answer:

Anna11 [10]2 years ago

8 0

Answer:

Xe:[Kr]4d¹⁰5(sp³d³)₆⁺² => Octahedral Geometry (AX₆)⁺²

Explanation:

Xe:[Kr]4d¹⁰(5s²5p₋₁²p₀²p₁²5d₋₂d₋₁d₀)⁺² => Xe[Kr]5(sp³d³)₆²

Ca. #Valence e⁻ = Xe + 6F - 2e⁻ = 1(8) + 6(7) - 2 = 48

Ca. #Substrate e⁻ = 6F = 6(8) = 48

#Nonbonded free pairs e⁻ = (V - S)/2 = (48 - 48)/2 = 0 free pairs

#Bonded pairs e⁻ = 6F substrates = 6 bonded pairs

BPr + NBPr = 6 + 0 = 6 e⁻ pairs => Geometry => [AX₆]⁺² => Octahedron

Xe:[Kr]4d¹⁰(5s²5p₋₁²p₀²p₁²5d₋₂d₋₁d₀)⁺² => Xe[Kr]5(sp³d³)₆⁺²

XeF₆⁺² => 6(sp³d³) hybrid orbitals => Octahedral Geometry (AX₆)

You might be interested in

Last question, I promise!!!!!! ... :>

VikaD [51]

Answer:

Which question?

Explanation:

3 0

3 years ago

Read 2 more answers

I don’t know how to solve this

stepladder [879]

Hi,

Answer is 191.2.

800J = 191.2 cal

Hope this helps.

7 0

3 years ago

What is the molar mass of CaCl2?

alekssr [168]

Molar mass of CaCl2 = 40+ ( 35.5 ×2)=110

Mr of Ca(OH)2 = 40+ (16+1)×2 =74

%of Ca = (40÷ 74)×10=...

1 m = 100cm...
1cm = (1÷100) m
So 45.5 cm = 45.5 ×(1÷100) =....

1km = 1000m
1m = 100 cm
1cm =10mm
So 1km = 1000×100×10 mm
Now convert

7 0

2 years ago

a flask contains 2 gases. the first gas has a pressure of 0.76 atm and the second gas gas a pressure of 4,500 Pa. what is the to

Liula [17]

Answer:

The total pressure is 0,804 atm

Explanation:

We use Dalton's law according to which the sum of the partial pressures is equal to the total pressure of a gas mixture. We convert the pressure in Pascals to atmosphere (it can also be done in reverse):

101300Pa ----1 atm

4500Pa----x= (4500Pa x 1atm)/101300Pa= 0,044 atm

P total= p1 + p2= 0,76 atm + 0,044 atm=0,804 atm

4 0

2 years ago

When fluorine gas combines with water vapor, the following reactions occurs.

jonny [76]

Hello!

The Chemical reaction is the following:

2F₂(g) + 2 H₂O(g) → O₂(g) + 4HF(g)

If we assume that all the gases are ideal gases, we can describe the coefficients of this reaction as Volume rather than moles, so we can apply the following equations:

$2 L F_2* \frac{2 L H_2O}{2 L F_2}=2 L H_2O \\ \\ 2 L F_2* \frac{1 mol O_2}{2 L F_2}=1 mol O_2 \\ \\ 2 L F_2* \frac{4 mol HF}{2 mol F_2}= 4 mol HF$

So, 2 L of Water Vapor reacts with the fluorine; and 1 L of Oxygen and 4 L of Hydrogen Fluoride are produced.

Have a nice day!

6 0

2 years ago