Molar mass 496.4200 g/mol
Number of moles:
40 g x 1 mol / 496.4200 => 0.08057 moles
Volume in liters:
250.0 mL / 1000 => 0.25 L
Therefore:
M = moles / V
M = 0.08057 / 0.25
= 0.32228 M
hope this helps!
Answer is: the solubility of silver oxalate is <span>a. 1.4 × 10-4 m.
</span>
<span>Chemical reaction
(dissociation) of silver oxalate in water:
Ag</span>₂C₂O₄(s) → 2Ag⁺(aq) + C₂O₄²⁻<span>(aq).
Ksp(Ag</span>₂C₂O₄) = [Ag⁺]²·[C₂O₄²⁻<span>].
[C</span>₂O₄²⁻] = x; solubility of oxalate ion.
[Ag⁺] = 2[C₂O₄²⁻<span>] = 2x
1.0·10</span>⁻¹¹ = (2x)² · x = 4x³.
x = ∛1.0·10⁻¹¹ ÷ 4.
x = 1.4·10⁻⁴ M.
Answer:
Rate will increase by 3 times
Explanation:
According to the law of mass action:-
The rate of the reaction is directly proportional to the active concentration of the reactant which each are raised to the experimentally determined coefficients which are known as orders. The rate is determined by the slowest step in the reaction mechanics.
Order of in the mass action law is the coefficient which is raised to the active concentration of the reactants. It is experimentally determined and can be zero, positive negative or fractional.
The order of the whole reaction is the sum of the order of each reactant which is raised to its power in the rate law.
Given that:- Rate law = ![k[NO_2][CO]](https://tex.z-dn.net/?f=k%5BNO_2%5D%5BCO%5D)
Thus, if the pressure is increased from 0.2 atm to 0.6 atm, means 3 times, rate will also increases 3 times.
Answer: The molarity of the sodium hydroxide solution is 1.16 M.
Explanation:
Given:
= 35 mL,
= 0.5 M
= 15 mL,
= ?
Formula used to calculate the molarity of the sodium hydroxide solution is as follows.

Substitute the values into above formula as follows.

Thus, we can conclude that the molarity of the sodium hydroxide solution is 1.16 M.
Answer:
15 mL
Explanation:
El valor de concentración de 4% v/v nos dice que de cada 100 mL de cerveza, 4 mL son de alcohol.
Con eso en mente podemos <u>calcular los mL de alcohol presentes en 375 mL</u>, de la siguiente forma:
En 375 mL de cerveza de concentración 4% v/v, hay 15 mL de alcohol.