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stellarik [79]
3 years ago
8

Why would other scientist want to see observations from your three trials

Chemistry
1 answer:
Vedmedyk [2.9K]3 years ago
3 0

Answer:

When we do multiple trials of the same experiment, we can make sure that our results are consistent and not altered by random events and are reliable. Multiple trials can be done at one time. E.g. If we were testing a new fertilizer, we could test it on lots of individual plants at the same time.

Hope that helped.x

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How many liters of cane juice is needed to supply 5g sucrose if cane juice contains 12% sucrose
pickupchik [31]

Given parameters:

Mass of sucrose  = 5g

Density of sucrose  = 1.12g/mL

Percentage of sucrose per liter of cane juice  = 12%

Unknown:

Volume of cane juice needed = ?

We need to establish the volume - density relationship. Density is the mass of a substance per unit volume.

Mathematically;

                Density  = \frac{mass}{volume}

Now solve for the volume of sucrose;

                  1.12g/mL = \frac{5}{Volume}

       Volume  = \frac{5}{1.12}    =  4.46mL   = 4.46 x 10⁻³L since 1000mL  = 1L

Since 12% of 1 liter of cane juice is sucrose;

                    12% of  x  liter of cane juice  = 4.46 x 10⁻³L

                   Volume of cane juice  = 4.46 x 10⁻³ x \frac{100}{12}   = 0.037L

Volume of cane juice is  0.037L

   

6 0
3 years ago
Why do you think adding water (dilution) changes how acidic or basic the liquid is? Explain your thinking.
exis [7]

Answer:

Diluting an acid reduces the concentration of the H+ ions that cause acidity, while diluting a base reduces the concentration of the OH- ions that cause basicity.

Explanation:

The pH scale covers a range between 0 and 14 pH. A pH of exactly 7 is neutral. pH values greater than 7 are basic, while pH values less than 7 are acidic. The pH scale is logarithmic with a base of 10, meaning each integer pH value is 10 times more acidic or basic than the one preceding or succeeding it respectively. For dilution to decrease the acidity or basicity of a solution, the solvent being used must be less acidic or basic than this solution.

Alternatively, an acidic diluent may be used to dilute a basic solution, or vice versa, in a neutralization reaction. Because of the logarithmic nature of the pH scale, diluting a strong acid or base even slightly causes its respective pH to rise or drop considerably. Weak acids and bases with pH values close to 7 are correspondingly not as affected by dilution.

5 0
3 years ago
Read 2 more answers
What is the weight of a 90kg man standing on Earth, where gᵉᵃʳᵗʰ = 9.82 m/s^2?
Ray Of Light [21]

Answer:

88.38 Kgm/s^2

Explanation:

Mass and weight are quite different terms .

Weight is defined as the amount of force exerted on the earth due to our mass and gravity of acceleration.

W=m*g

Given that the mass is 90 kg and gravity of acceleration of earth is 9.82 m/s^2.

So weight will be

W=90*9.82\\\\ W=88.38 Kgm/s^2

So this is the weight of the 90kg man standing on earth.

7 0
3 years ago
Calculate the percent ionization of a 0.15 M benzoic acid solution in pure water and in a solution containing 0.10 M sodium benz
Hoochie [10]

Answer:

% ionization for benzoic acid = 0.08%

% ionization for sodium benzoate = 2.5%

The percentage ionization differ significantly because benzoic acid is a weak acid while sodium benzoate is a salt of benzoic acid. Their extent of dissociation also differ because they were compared in different solutions

Explanation:

Ka for pure water = 1.0 * 10-⁷

Ka for sodium benzoate = 6.5*10-⁵

1. For benzoic acid (C6H5COOH)

C6H5COOH ==== C6H5COO‐ + H+

0.15M 0 0

0.15-x x x

Ka = [C6H5COO-] [H+] / [C6H5COOH]

Ka = [X] [X] / 0.15 - X

1.0*10-⁷ = [X]² / 0.15 - x

But x is negligible compared to 0.15,

(1.0*10-⁷)*0.15 = x²

Take square root of both sides,

X = 1.22 * 10-⁴

% ionization = ( [H+] / [C6H5COOH] ) * 100

% ionization = (1.22*10-⁷ / 0.15) * 100

% ionization = 0.08%

2. For C6H5COONa

Note: I will not repeat the same procedure of dissociation again since they're basically the same just the difference in ions

Ka for C6H5COONa = 6.5*10-⁵

6.5*10-⁵ = [X]² / (0.10 - X)

Cross-multiply both sides;

(6.5*10-⁵ * 0.10) = X²

Take square root of both side,

X= 2.5*10-³

% ionization = (2.5*10-³ / 0.10) *100

% ionization = 2.5%

5 0
3 years ago
In which states of matter can an object change both volume and shape
Masja [62]

Answer:

Liquid

Explanation: Obviously

4 0
3 years ago
Read 2 more answers
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