A colony of amoebas is being studied. The mass of the colony triples every day. On Day x of the study, the colony has a mass of
3 ^ x mg. a. What is the mass of the colony on Days 3, 2 and 1? What is the mass of the colony on Day 0, when the study begins? Show your work .
1 answer:
Answer:
mass on day 1: 3
mass on day 2: 9
mass on day 3: 27
Step-by-step explanation:
using this equation, y = 3^x, you can plug in 1, 2, and 3 for 'x' to get the value of 'y' (which represents the mass on specific days)
3^1 = 3
3^2 = 9
3^3 = 27
You might be interested in
Answer:50.27
Step-by-step explanation:
Answer: I'm on it give me just a minute!!
Answer:
A) 41
Step-by-step explanation:
Let the hypotenuse be denoted by h
perpendicular as p and base as b
According to the Pythagoras theorem
h²=p²+b²
Answer:
Step-by-step explanation:
Let J = Jerry's age
Let M = Mary's age = 2J
M - 16 = J + 16
Substitute 2J for Mary's age
2J - 16 = J + 16
2J - J - 16 = 16
J = 16 + 16
J = 32
Jerry is 32.
Mary is twice as old as Jerry.
Mary is 2(32) = 64
<span>m = 4a + 2c
a = 25; c = 5
Replace a with 25. Replace c with 5.
Then evaluate the expression.
m = 4 * 25 + 2 * 5
m = 100 + 10
m = 110
Answer: 110 meatballs are needed.</span>
