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irga5000 [103]
3 years ago
5

A ball is thrown vertically upward from the ground with an initial velocity of 111 ft/sec. Use the quadratic function h(t) = −16

t2 + 111t + 0 to find how long it will take for the ball to reach its maximum height (in seconds), and then find the maximum height (in feet). (Round your answers to the nearest tenth.)
Mathematics
1 answer:
ddd [48]3 years ago
4 0

Answer:

t=3.5 seconds

Step-by-step explanation:

Given

h(t) = −16t^2 + 111t + 0

h'(t)= -32t + 111

Maximum height occurs when h(t) = 0 and the ball begins to fall

h(t)= -32t + 111=0

-32t + 111=0

-32t=-111

Divide both sides by -32

t=3.46872

Approximately, t=3.5 seconds

Recall,

Maximum height occurs when h(t) = 0

h(t)= -32t + 111=0

= -32(3.46872)+111

= -110.99904+111

= 0.00096 ft

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Answer:

We conclude that the actual percentage of households is equal to 30%.

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Let p = <u><em>proportion of households that have three cell phones NOT known.</em></u>

So, Null Hypothesis, H_0 : p = 30%      {means that the actual percentage of households is equal to 30%}

Alternate Hypothesis, H_A : p \neq 30%     {means that the actual percentage of households different from 30%}

The test statistics that would be used here <u>One-sample z-test for proportions;</u>

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where, \hat p = sample proportion of households having three cell phones = \frac{43}{150} = 0.29

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The value of z test statistic is -0.27.

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