Having a polygon inscribed in a circle divides the circle into equal parts, equal to the amount of sides the polygon has. In the case of a regular octagon inscribed in a circle, the circle is divided into 8 equal parts because of this. Since the measure of a whole circle is 360 degrees, an arc formed by an octagon is equal to 360 divided by 8.
Arc = 360 degrees / 8 = 45 degrees.
56 units are in the sum of the lengths of the three altitudes in a triangle with sides $7,$ $24,$ and $25$
Properties of triangles are:
A triangle has three sides and three angles.
The sum of the angles of a triangle is always 180 degrees.
The exterior angles of a triangle always add up to 360 degrees.
The sum of consecutive interior and exterior angle is supplementary.
<h3 /><h3>How to solve?</h3>
Given:
Height: ha = 7
Height: hb = 24
Height: hc = 25
Sum to sides is:
25 +7 + 24 =56 units.
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I would put 9 and 1/2 because there boots they have about 1 size differnce
Answer:
t = - 3, t = - 1
Step-by-step explanation:
Given
h(t) = t² + 4t + 3
To find the zeros equate h(t) to zero, that is
t² + 4t + 3 = 0
Consider the factors of the constant term (+ 3) which sum to give the coefficient of the t- term
The factors are + 3 and + 1, since
3 × 1 = 3 and 3 + 1 = 4, thus
t² + 4t + 3 = (t + 3)(t + 1) = 0
Equate each factor to 0 and solve for t
t + 3 = 0 ⇒ t = - 3
t + 1 = 0 ⇒ t = - 1
smaller zero is t = - 3
larger zero is t = - 1
Answer:
8-5
Step-by-step explanation: