Answer:
The original price of the shoes was $90.
Step-by-step explanation:
25% off means the price Joe paid for it is 75% of the original price.
Set up an equation:
75/100 = 67.50/x
Cross multiply
75 × x = 100 × 67.50
75x = 6750
x = 90
Check our work:
First solve for 25% off of 90 (our answer).
25% = 0.25
90 × 0.25 = 22.50
Next, subtract the discount from 90.
90 - 22.50 = 67.50
67.50 was what Joe paid so this is correct.
(9-4) + 3•8 = 29
Explanation
First you need to apply the PEMDAS rule
Parentheses
Exponents
Multiplication
Division
Addition
Subtract
So when solving the problem you first have to solve what’s in Parentheses first. So (9-4) which would equal 5
Next, according to the PEMDAS rule you’d have to do multiplication next. So 3•8 is equal to 24
And finally, the last step is Addition. After you’ve done the Parentheses and Multiplication you have to add up your answers. 5+24 would be 29
Answer= 29
Answer: -3z+8
Step-by-step explanation: add -4z and z because they are like terms and then leave the 8 alone because it’s a term.
Answer: The percentile is 89
Step-by-step explanation:
This question can be solved using concept for t tables
In a normal distribution the curve. 
The relationship between z score, mean and standard deviation is given by

So the z value according to this is given by the formula

From the z table we can infer that p value for z=+1.217 is 88.82
So 1750 is 89th percentile
To learn more about statistics, visit brainly.com/question/26352252
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Answer:
<em>255</em>
Step-by-step explanation:
(2+2+3+10) × (8+9+-9+7)
First, remove the brackets:
2 + 2 + 3 + 10 × 8 + 9 + -9 + 7
Now calculate like so:
2 + 2 + 3 + 10 = <em>17</em>
8 + 9 + -9 + 7 = <em>15</em>
<em>(</em><em>17</em><em>)</em><em> </em><em>×</em><em> </em><em>(</em><em>15</em><em>)</em><em> </em><em>=</em><em> </em><em>17</em><em> </em><em>×</em><em> </em><em>15</em><em> </em><em>=</em><em> </em><em>255</em>
<em>PLEASE</em><em> </em><em>DO</em><em> </em><em>MARK</em><em> </em><em>ME</em><em> </em><em>AS</em><em> </em><em>BRAINLIEST UWU</em><em> </em>