In real-life physics, acceleration due to gravity will change respect to altitude. Check out the attached image (source: Wikipedia).
However, in high-school physics, acceleration due to gravity is represented by the letter g, which has a value of 9.81 meters per second squared.
This means that an object being dropped straight down will be moving 9.81 meters per second faster than it was 1 second ago. I hope this helps! :)
Answer: option d. x = 3π/2Solution:function y = sec(x)
1) y = 1 / cos(x)
2) When cos(x) = 0, 1 / cos(x) is not defined
3) cos(x) = 0 when x = π/2, 3π/2, 5π/2, 7π/2, ...
4) limit of sec(x) = lim of 1 / cos(x).
When x approaches π/2, 3π/2, 5π/2, 7π/2, ... the limit →+/- ∞.
So, x = π/2, x = 3π/2, x = 5π/2, ... are vertical asymptotes of sec(x).
Answer: 3π/2
The figures attached will help you to understand the graph and the existence of multiple asymptotes for y = sec(x).
I need to see the answers choices so answer
To get the x-intercept you put y=0
0=2x-8
2x=8 , x=4
the point is (4,0)