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Vlada [557]
2 years ago
14

Choose the most convenient method to graph the line x - y = 5.

Mathematics
2 answers:
givi [52]2 years ago
7 0
The most convenient method I would choose is slope-intercept form, which is y=mx+b. So, make this equation equal in terms of y.

x-y=5
subtract x from both sides
-y = 5 - x
multiply both sides by -1 so y isn't negative
y = 5 + x
5 +x is the same thing as x+5, so
y = x+5

Now, you can easily sub in any number for x and you can easily get y. Here are some points you can plot:

(0, 5), (1, 6), (2, 7), (3, 8) and the list goes on. I hope this helped!
dmitriy555 [2]2 years ago
7 0

Answer:

Step-by-step explanation:

x - y = 5

Write in slope-intercept form: y = mx +b

-y = -x + 5

Multiply the entire equation by(-1)

y = x - 5

When x = 0 ; y = 0 - 5 = -5    ;              (0,-5)

When x = 1  ; y = 1 - 5 = - 4     ;              (1 , -4)

When x = 4 ; y =  4 - 5 = -1      ;              (4 , -1)

When x = -1 ; y = -1 - 5 = - 6      ;           (-1,-6)

Plot the points and join the points

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What is the length of the hypotenuse of the right triangle if one side is 16in and one is 7in?
Ronch [10]

Answer:

hypotenuse = 17.46

Step-by-step explanation:

The Pythagorean Theorem is a^2+b^2=c^2.

Since we are finding the hypotenuse, we must plug in 16 and 7 since they represent the lengths of both side.

16^2+7^2=c^2

256+49=c^2

305=c^2

which means we have to find the square root of c^2 AND 305, round it to the nearest hundredth, which means that;

c=17.46

7 0
3 years ago
A 2x2 square is centered on the origin. It is dilated by a factor of 3. What are the coordinated of the vertices of the square?
Alexxx [7]

<u>Answer</u>:

The vertices are:

A' = (-3, -3)

B' = (3, -3)

C' = (3, 3)

D' = (-3, 3)

The ratio of area of  larger square to smaller square is 9:1

<u>Step-by-step explanation:</u>

Given:

A 2 x 2 square is centered at the origin.

So, the center of the square is (0, 0)

Since it is 2 x 2 square, the side of the square is 2 units.

So, the vertices of the 2 x 2 square are A (-1, -1),  B(1, -1), C(1. 1), D(-1, 1)

The above square is dilated by a factor of 3.

Let's name the dilated square A'B'C'D'

To find the coordinates of the vertices of dilated square, we need to multiply each vertices of ABCD by 3.

A(-1, -1) = 3(-1, -1) = A'(-3, -3)

B(1, -1) = 3(1, -1) = B'(3, -3)

C(1, 1) = 3(1, 1) = C'(3, 3)

D(-1, 1) = 3(-1, 1) = D'(-3, 3)

To find the area of the small square

the side  of the small square is 2 units

so the are of the small square is 2^2 = 4 square units

To find the area of the larger square

lets find the side AB of the square using distance formula

=>\sqrt{(x_2 -x_1)^2 +(y_2-y_1)^2}

=>\sqrt{(3 - (-3))^2 +(-3 - (-3))^2}

=>\sqrt{(3 +3)^2 +(-3 +3)^2}

=>\sqrt{(6)^2 +(0)^2}

=>\sqrt{36}

=>6

AB =6 units

In a square all the sides will be equal

Now the area of the larger square will be

6^2

36 square units

The ratio of larger square to smaller square is

=>36 : 4

=>9 : 1

5 0
3 years ago
Hi guys could some please help me answer this question???
qaws [65]

Answer: the bottom one

Step-by-step explanation:

i think its the bottom one i did some math

8 0
2 years ago
8x - 5 - 6 - 7 <br> Can someone solve this
Iteru [2.4K]

Answer:

8x-18

Step-by-step explanation:

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4 0
3 years ago
Read 2 more answers
10 POINTS!
katrin2010 [14]

Answer:

A = yes

B = no

C = yes

D = no

E = yes

F = yes

Hope I helped!!!

7 0
2 years ago
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