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nika2105 [10]
3 years ago
7

What is the slope of the line shown in the graph? -1 -2 -1/2 2

Mathematics
2 answers:
kow [346]3 years ago
6 0

Answer:

Slope is -2

Step-by-step explanation:

MissTica3 years ago
3 0

Answer:

The slope would would be -2

Step-by-step explanation:

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Plzzz help as soon as possible
Anika [276]

Answer:

Step-by-step explanation:

8 is not a function

9 is a function

10 is a function

4 0
3 years ago
The Lewis family is building a circular swimming pool if the radius of the pool is 9 feet what is it’s circumference use TT =3.1
zzz [600]

Answer:

C =56.52 ft

Step-by-step explanation:

The circumference is found by

C = 2*pi*r  where r is the radius

C = 2*3.14 * 9

C =56.52 ft

5 0
3 years ago
Which list contains ONLY irrational numbers?
Black_prince [1.1K]
The first choice is the contains only irrational number
8 0
3 years ago
Read 2 more answers
HELP! SIMPLIFY!
Vitek1552 [10]
1)  (m³n⁵)(mn⁴)
     -----------------
      m⁻³n²

Simplify.

m⁴n⁹
-------
m⁻³n²

When the bottom power is a negative, you add it to the power on top, & when the power is a positive, you subtract it.

m⁴ + m³ = m⁷

n⁹ - n² = n⁷

So, our answer for #1 is m⁷n⁷

2)  6a²b³
     ---------
        4a

Please read rules in #1.

6 / 4 = 3/2 & a² - a = a

So, our answer is 3a
                               -----
                                 2

3)  5⁶a⁶b³
     ---------
       5²ab³
5⁶ - 5² = 5⁴ AND a⁶ - a = a⁵ AND b³-b³ = 0

So, our answer is 5⁴a⁵

Simplify 5⁴

5 × 5 × 5 × 5 = 625

So, our final answer is :

625a⁵

~Hope I helped!~
6 0
3 years ago
If a = √3-√11 and b = 1 /a, then find a² - b²​
Serga [27]

If b=\frac1a, then by rationalizing the denominator we can rewrite

b = \dfrac1{\sqrt3-\sqrt{11}} \times \dfrac{\sqrt3+\sqrt{11}}{\sqrt3+\sqrt{11}} = \dfrac{\sqrt3+\sqrt{11}}{\left(\sqrt3\right)^2-\left(\sqrt{11}\right)^2} = -\dfrac{\sqrt3+\sqrt{11}}8

Now,

a^2 - b^2 = (a-b) (a+b)

and

a - b = \sqrt3 - \sqrt{11} + \dfrac{\sqrt3 + \sqrt{11}}8 = \dfrac{9\sqrt3 - 7\sqrt{11}}8

a + b = \sqrt3 - \sqrt{11} - \dfrac{\sqrt3 + \sqrt{11}}8 = \dfrac{7\sqrt3 - 9\sqrt{11}}8

\implies a^2 - b^2 = \dfrac{\left(9\sqrt3 - 7\sqrt{11}\right) \left(7\sqrt3 - 9\sqrt{11}\right)}{64} = \boxed{\dfrac{441 - 65\sqrt{33}}{32}}

5 0
2 years ago
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