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Lunna [17]
3 years ago
9

Rotate the figure shown 180° clockwise. Record the coordinates of the image.

Mathematics
1 answer:
Mariulka [41]3 years ago
3 0

Answer:

where's the image?

Step-by-step explanation:

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during his first year as a pilot, rob flies 6,692 miles. he flies 16,429 miles the second year and 24,211 miles the third year.
emmainna [20.7K]

First years flies = 6,692 miles ≈7000 miles.

Second year flies =  16,429 miles ≈ 16000.

Third year flies = 24,211 miles ≈ 24000

Total number of miles flies in first and second year = 7,000miles +16,000 miles

Number of more miles he flew in the third year than the first and second year combined = Number of miles flies in third year - Total number of miles flies in first and second year

Number of more miles he flew in the third year than the first and second year combined 24,000 - (7,000+16,000)

Therefore, 24,000 - (7,000+16,000) estimation of how many more miles he flew in the third year than the first and second year combined.

6 0
3 years ago
A) b³(cm)³
Crazy boy [7]

Answer:

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4 0
3 years ago
Help me with the attached question please
sergejj [24]

Answer:

284.72

Step-by-step explanation:

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6 0
2 years ago
Write an equation for the data. x y 0 0 2 –4 4 –8 6 –12 A. y = 2x – 2 B. y = 2x C. y = –2x D. y = x + 2
daser333 [38]

Answer:

C. y = -2x.

Step-by-step explanation:

x y

0 0

2 -4

4 - 8

6 -12

Note that the y values = x values * -2,

so the equation is y = -2x.

8 0
3 years ago
<img src="https://tex.z-dn.net/?f=y%20%3D%20%20%5Cfrac%7B%28190%29%5E%7B3%7D%20%7B68%5E%7B2%7D%20%7D%20%20%5Ctimes%20%28%20%5Cfr
mrs_skeptik [129]

Answer:

  \dfrac{\sqrt[3]{95^2}}{17\cdot95^4}=\dfrac{\sqrt[3]{9\,025}}{1\,384\,660\,625}

Step-by-step explanation:

The applicable rules of exponents are ...

  (ab)^c = (a^c)(b^c)

  (a^b)/(a^c) = a^(b-c)

__

  \dfrac{190^3}{68^2}\times\dfrac{34}{95^{\frac{19}{3}}}=\dfrac{(2\cdot 95)^3}{(2\cdot 34)^2}\cdot\dfrac{34}{95^6\cdot 95^{\frac{1}{3}}}=2^{3-2}95^{3-6-\frac{1}{3}}34^{1-2}\\\\=2\cdot 95^{-3\frac{1}{3}}\cdot 34^{-1}=2\cdot 95^{-4+\frac{2}{3}}\cdot 34^{-1}\\\\=\dfrac{2\sqrt[3]{95^2}}{95^4\cdot 34}=\dfrac{\sqrt[3]{95^2}}{17\cdot95^4}\\\\=\dfrac{\sqrt[3]{9\,025}}{1\,384\,660\,625}

6 0
3 years ago
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