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Digiron [165]
2 years ago
13

I really need help fast and ill do anything just help me plz

Mathematics
1 answer:
podryga [215]2 years ago
3 0
Answer is C. 12.22cm

C = pi x diameter

Diameter = 20cm

You times pi by 20cm (diameter) to get the circumference of approx 62.84cm

Then times the circumference by the angle in the circle

62.84 x 70/360 = 12.22cm

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Answer:

Last option (bottom right)

Step-by-step explanation:

The scientific notation for 0.002 is 2*10^-3 (you move the decimal 3 to the right to get 2)

multiply the number of mustard seeds with this and you get 80. In scientific notation it is 8*10^1 (move the decimal 1 to the left to get 8.0)

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2 years ago
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maria [59]

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7 0
3 years ago
Read 2 more answers
plz help whats the answer to this question !!! calculate the mass of a gold bar that is 18.00cm long, 9.21cm wide, and 4.45cm hi
erik [133]

We have to find the mass of the gold bar.

We have gold bar in the shape of a rectangular prism.

The length, width, and the height of the gold bar is 18.00 centimeters, 9.21 centimeters, and 4.45 centimeters respectively.

First of all we will find the volume of the gold bar which is given by the volume of rectangular prism:

Volume of the gold bar = length \times width\times height

Plugging the values in the equation we get,

Volume of the gold bar =18.00 \times 9.21 \times 4.45= 737.721cm^3

Now that we have the volume we can find the mass by using the formula,

Mass= density \times volume

The density of the gold is 19.32 grams per cubic centimeter. Plugging in the values of density and volume we get:

Mass = 19.32\times 737.721=14252.769 grams

So, the mass of the gold bar is 14252.769 grams

7 0
3 years ago
Please help me !!!
ad-work [718]

Answer:

x = 47

2x+6 = 100  which is the angle measure

Step-by-step explanation:

The angles are vertical and vertical angles are equal

2x+6 = 100

Subtract 6 from each side

2x+6-6 =100-6

2x = 94

Divide by 2

2x/2 = 94/2

x =47

Now to find the measure of 2x+6

We know that it is equal to 100

so 2x+6 = 100

6 0
2 years ago
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