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scoundrel [369]
3 years ago
12

Select all the equations where x = 3 is a solution.

Mathematics
2 answers:
inna [77]3 years ago
7 0

\huge\text{Hey there!}

\large\text{x = 3}

\large\textsf{Option A.}\downarrow\\\\\mathsf{x + 4 = 7}\\\mathsf{x = 3}\\\mathsf{3+4=7}\\\mathsf{3+4 =\bf 7}\\\mathsf{7 = 7}\\\\\\\large\text{Option A. could possibly be your answer}\checkmark

\large\textsf{Option B. }\downarrow\\\\\mathsf{\dfrac{x}{9}=3}\\\\\mathsf{x = 3}\\\\\mathsf{\dfrac{3}{9}=3}\\\\\mathsf{\dfrac{3}{9}= \dfrac{1}{3}=\bf 0.333333}\\\\\mathsf{0.333333\neq 3}\\\\\large\text{Option B. is NOT your possible answer}

\large\textsf{Option C. }\downarrow\\\mathsf{5-x =2}\\\mathsf{x = 3}\\\mathsf{5-3=2}\\\mathsf{5-3=\bf 2}\\\mathsf{2=2}\\\\\large\text{Option C. could possibly be your answer}\checkmark

\large\textsf{Option D. }\downarrow\\\\\mathsf{8x = 32}\\\mathsf{x =3}\\\mathsf{8(3)=\bf 24}\\\mathsf{24\neq 32}\\\\\large\text{Option D. is NOT your possible answer}

\large\textsf{Option E. }\downarrow\\\mathsf{x - 10=7}\\\mathsf{x =3}\\\mathsf{3-10=7}\\\mathsf{3-10=\bf -7}\\\mathsf{-7\neq7}\\\\\large\text{Option E. is NOT your possible answer}

\boxed{\large\text{Answer: \boxed{\large\text{\bf Option A. x + 4 = 7 \& Option C. 5 - x = 2}}}}\huge\checkmark

\text{Good luck on your assignment and enjoy your day!}

~\frak{Amphitrite1040:)}

Alex777 [14]3 years ago
5 0

Answer: A and C

Step-by-step explanation:

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3 years ago
Read 2 more answers
How do I work this out?
zvonat [6]

We have to determine the value of \sum _{m=9} ^{21} (5m+6)

= (5(9)+6) + (5(10)+6) +(5(11)+6) + .......... + (5(21)+6)

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8 0
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