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2 years ago

13

Triangle OMG has vertices O (6, 4), M (-8, 0), G (2, -2). It is dilated and the image coordinates are O' (3, 2) M' (-4, 0) G' (1

, -1). What is the scale factor of the dilation?

2 answers:

Harlamova29_29 [7]2 years ago

6 0

Answer:

O(6,4)ML,(80),-G(2-2

KengaRu [80]2 years ago

3 0

O (6,4), M (-8,0), G (2,-2)

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Find the area of the triangle with the given base and height.<br> b = 3 m and h = 10 1/2 m

svetoff [14.1K]

<u>Statement</u><u>:</u>

The base of a triangle is 3m and its height is $10 \frac{1}{2}$ m.

<u>To </u><u>find </u><u>out:</u>

The area of the triangle.

<u>Solution:</u>

Given, base = 3m, height = $10 \frac{1}{2}$ m
We know,

$\sf \: area \: \: of \: \: a \: \: triangle = \frac{1}{2} \times base \: \times height$

Therefore, the area of the triangle

$\sf = (\frac{1}{2} \times 3 \times 10 \frac{1}{2} ) {m}^{2} \\ \sf = ( \frac{1}{2} \times 3 \times \frac{21}{2} ) {m}^{2} \\ = \sf \frac{63}{4} {m}^{2} \\ = \sf 15\frac{3}{4} {m}^{2}$

<u>Answer</u><u>:</u>

The area of the triangle is $\sf \: 15 \frac{3}{4} {m}^{2}$

Hope you could understand.

If you have any query, feel free to ask.

5 0

2 years ago

Read 2 more answers

I need this question to be answer asap

myrzilka [38]

If r(x)= 11x, and c(x)=6x +20, then just put that into the equation.
So instead of p(x) = r(x) - c(x)
I would be p(x) = 11x - 6x + 20
Now solve.
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7 0

3 years ago

Read 2 more answers

Efectuati!<br> (-1)+2+(-3)+4+(-5)+...+(-19)+20<br> Ajutati-ma, va rog!

alexira [117]

Answer:10

Step-by-step explanation:

2+4+6+.....+20- (1+3+5+7+...+19)=(2-1)+(4-3)+(6-5)+....+(20-19)=1+1+...+1 ( de 10 ori= 10 times)

=10

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3 years ago

A study shows that 20% of college students pray daily in their own religious beliefs. In a group of 300 college students, find t

svetlana [45]

Answer:

0.2805

Step-by-step explanation:

Given that p = 20% = 0.2, n = 300.

The mean (μ) = np = 0.2 * 300 = 60

The standard deviation (σ) = $\sqrt{np(1-p)}=\sqrt{300*0.2(1-0.2)}=6.93$

The z score is used to determine by how many standard deviations the raw score is above or below the mean. The z score is given by:

$z=\frac{x-\mu}{\sigma }$

For x = 57:

$z=\frac{57-60}{6.93 } =-0.43$

For x = 62:

$z=\frac{62-60}{6.93 } =0.29$

From the normal distribution table, P(57 < x < 62) = P(-0.43 < z < 0.29) = P(z < 0.29) - P(z < -0.43) = 0.6141 - 0.3336 = 0.2805

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2 years ago

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Ivan

Wouldent the answer be A because all percents are out of 100 so the 1.9 would be 9 over 100

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3 years ago