Answer:
3. Sides: Equilateral
Angles: Acute
4. Sides: Isosceles
Angles: Right
Step-by-step explanation:
3. Sides: Equilateral because in an equilateral triangle all sides are equal.
Angles: Acute because in an acute triangle all angles are acute.
4. Sides: Isosceles because in an isosceles triangle two legs are equal.
Angles: Right because in a right triangle, one angle is right.
Answer:
X = 5
Step-by-step explanation:
Here is what I am picturing (not to scale)
A ----------------B-----------C
We are given the information of AB (which equals 3x + 1), BC (which equals 4x - 5), and AC (which equals 8x - 9).
With reference to the line, AB + BC = AC
So,
3x + 1 + 4x - 5 = 8x - 9
7x - 4 = 8x - 9
5 = x
There aren't any answer options so I will just simplify the expression:
10(2p+q)
20p+10q
Answer:
no real solutions
Step-by-step explanation:
Given a quadratic equation in standard form
ax² + bx + c = 0 : a ≠ 0
Then the nature of the roots can be determined from the discriminant
b² - 4ac
• If b² - 4ac > 0 then 2 real and distinct roots
• If b² - 4ac = 0 then 2 real and equal roots
• If b² - 4ac < 0 then no real roots
Given
n(7n + 8) = - 10 ← distribute left side
7n² + 8n = - 10 ( add 10 to both sides )
7n² + 8n + 10 = 0 ← in standard form
with a = 7, b = 8 and c = 10, thus
b² - 4ac = 8² - (4 × 7 × 10) = 64 - 280 = - 216
Since b² - 4ac < 0 the equation has no real roots
