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tigry1 [53]
3 years ago
15

Propane, the gas that is used in barbecue grills, is mad of carbon and hydrogen.Will the atoms that make up propane from covalen

t bones? Why or why not
Physics
2 answers:
nika2105 [10]3 years ago
7 0

Answer:

Atoms that make up propane are hydrogen and carbon and they will form covalent bonds because they are non - metals.

Explanation:

Formula for propane is C3H8.

This means is is made up of Carbon and hydrogen.

Covalent bonding is defined as the process of sharing of electrons between atoms. Now, this type of bonding occurs between two atoms of the same element or elements that are close to one another in the periodic table. This suggests that the covalent bonding will occur primarily between nonmetals.

Now, the atoms of propane are made up of Carbon and hydrogen. These elements are non-metal and thus as described about covalent bonds, they will form covalent bonds because theg are both nonmetals.

Leviafan [203]3 years ago
6 0

Answer:

The atoms of propane will form covalent bonds because carbon and hydrogen are both nonmetals.

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In a Horsehoe magnet, maximum magnetic field is concentrated between the poles.

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8 0
3 years ago
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An electron is moving through a magnetic field whose magnitude is 9.21 × 10^-4 T. The electron experiences only a magnetic force
Marysya12 [62]

Answer:

\theta=10.60^{\circ}

Explanation:

Given that,

Magnetic field, B=9.21\times 10^{-4}\ T

Acceleration of the electron, a=2.3\times 10^{14}\ m/s^2

Speed of electron, v=7.69\times 10^{6}\ m/s

The force due to this acceleration is balanced by the magnetic force as :

ma=qvB\ sin\theta

sin\theta=\dfrac{ma}{qvB}

sin\theta=\dfrac{9.1\times 10^{-31}\times 2.3\times 10^{14}}{1.6\times 10^{-19}\times 7.69\times 10^{6}\times 9.21\times 10^{-4}}

\theta=10.60^{\circ}

So, the angle between the electron's velocity and the magnetic field is 10.6 degrees. Hence, this is the required solution,

8 0
4 years ago
Steam enters an adiabatic turbine at 6 MPa, 600 ℃, and 80 m/s and leaves at 50 kPa, 100 ℃, and 140 m/s. If the power output of t
lisabon 2012 [21]

Answer:

W(r,out) = 5.81 MW

\eta = 86.1 %

Explanation:

we use here steam table for get value of h1, s1 etc

so use for 6MPa and 600 degree

Enthalphy of steam h1 = 3658.8 kJ/kg

Entropy of steam s 1 is = 7.1693 kJ /kg.K

and

for 50 kPa and 100 degree

Enthalphy of steam h2 = 2682.4 kJ/kg

Entropy of steam s2 is = 7.6953 kJ /kg.K

so we use here energy balance equation that is

m\times(h1 + \frac{v1^2}{2} = m\times(h2 + \frac{v2^2}{2} + W(out)      ..............1

put here value and we get m

m = \frac{5\times1000}{3658.8-2682.4+\frac{80^2-140^2}{2}\times \frac{1}{1000}}  

solve it we get

m = 5.156 kg/s

so by energy balance equation

m\psi1 = m\psi2 + W(r,out)

W(r,out) = m(\psi1 -\psi2)

W(r,out) = h1 - h2 + ΔKE + ΔPE - To(s1-s2)

W(r,out) = m[h1-h2+ \frac{v1^2-v^2}{2}- To (s1-s2)

W(r,out) = W(a,out) - m.To.(s1-s2)     ........................2

put here value

W(r,out) = 5000 - ( 5.156 × (25 + 273) ×( 7.1693 - 7.6953)

W(r,out) = 5908.19 = 5.81 MW

and

second law deficiency is

\eta = \frac{W(a,out)}{W(r,out)}     ..............................3

put here value

\eta = \frac{5}{5.81}

\eta = 86.1 %

6 0
3 years ago
Describe how you will show J. J. Thomson's model of the atom using small beads and clay
antoniya [11.8K]
You would make rings of clay and then place the beads on the rings (one on each) at various places and one in the center for the nucleus.

8 0
3 years ago
I need help by today
babymother [125]

The answer is B. Well it's the best answer.

6 0
4 years ago
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