Answer:
The area of the gold foil is
Explanation:
Mass of gold foil , m= 27.63 g
Thickness of gold foil ,
Density of gold ,
Let the area of gold foil be A then the total volume of gold foil is given by
=>
=>
Thus the area of the gold foil is
Answer:
Explanation:
Radius of circular path of coin R = 12.5 x 10⁻²,
coefficient of static friction μs = .33
In order that the coin rotates in circular path , it requires centripetal force which is provided by friction. As speed of rotation increases , force of friction also increases to provide it required centripetal force. When the speed of rotation becomes too high so that frictional force can not compensate the increase in centripetal force then coin will start slipping or it starts moving with respect to turntable.
b ) At this point of time
centripetal force = limiting force of friction
mω² R = μs mg , m is mass of the coin , ω is angular velocity ,
ω² R = μs g
ω² x 12.5 x 10⁻², = .33 x 9.8
ω² = .33 x 9.8 / 12.5 x 10⁻²,
= 25.87
ω = 5.08 rad / s
2π / T = 5.08
T = 2π / 5.08
= 1.23 s .
Answer:
<h2>31km/h</h2>
Explanation:
Step one:
given data
speed of bus= 35km/h forward
speed of ball= 4km/h backwards
`Step two:
Required
the magnitude of the velocity of the ball relative to the ground is the net velocity
that is
=35-4
=31km/h
<em><u>The velocity of the ball relative to the ground is 31km/h</u></em>
Nothing, ATOMS lose or gain electrons to become IONS
<span>Two Na ATOMS lose 1 electron each and 1 S ATOM gains 2 electrons </span>
Answer:h=19.4 m
Explanation:
Given
mass of automobile
Initial height of automobile
Velocity at this instant
If the car stops somewhere at a height
Thus conserving total energy we get