Explanation:
Suppose the cheetah is initially positioned at x=0 (m) from the reference, and the gazelle is intially at poisiton x=d (m).
Then, at the worst case, that is when cheetah is running at the maximum case, the position of the gazelle relative to the reference must be larger than that of cheetah.
In equation form,
A 16.0 kg crate increases in height from 1.80 m to 3.30 m above the floor. The increase in potential energy is 240 J (a).
<h3>What is potential energy?</h3>
It is the energy due to the position.
A 16.0 kg (m) crate rests on a shelf 1.80 m (h₁) above the floor in a warehouse. The potential energy is:
U₁ = m × g × h₁ = 16.0 kg × (9.81 m/s²) × 1.80 m = 283 J
A forklift is used to raise the crate to a shelf 3.30 m (h₂) above the warehouse floor. The potential energy is:
U₂ = m × g × h₂ = 16.0 kg × (9.81 m/s²) × 3.30 m = 518 J
The increase in the potential energy is:
518 J - 283 J = 235 J ≈ 240 J
A 16.0 kg crate increases in height from 1.80 m to 3.30 m above the floor. The increase in potential energy is 240 J (a).
Learn more about potential energy here: brainly.com/question/23979653
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Answer:
Condensation
Explanation:
Condensation is the process by which water vapor in the air is changed into liquid water. Condensation is crucial to the water cycle because it is responsible for the formation of clouds.
Answer:
h = 2.087 m
Explanation:
Given
m₁ = 3 kg
v₁ = 20 m/s
m₂ = 2 kg
v₂ = - 14 m/s
In a completely inelastic collision the colliding objects stick together after the collision and move together as a single object.
In the given problem, lets assume that the balls of putty are initially moving along the y axis, upward direction being the positive y direction. And the collision occurs at the origin of the coordinate system.
We can apply the equation
vs = (m₁*v₁ + m₂*v₂) / (m₁ + m₂)
⇒ vs = (3 kg*20 m/s + 2 kg*(- 14 m/s)) / (3 kg + 2 kg)
⇒ vs = 6.4 m/s (↑)
To calculate the maximum height h attained by the combined system of two balls of putty after the the collision, we use the expression for linear motion under gravity:
vf² = vi² - 2*g*h
where
vf = 0 m/s
g = 9.81 m/s²
vi = vs = 6.4 m/s
finally we get h:
h = vi² / (2*g)
⇒ h = (6.4 m/s)² / (2*9.81 m/s²) = 2.087 m
Answer:
(a) 
(b) 
(c) 
(d) 
Solution:
As per the question:
Angular velocity, 
Time taken by the wheel to stop, t = 2.4 h = 
Distance from the axis, R = 38 cm = 0.38 m
Now,
(a) To calculate the constant angular velocity, suing Kinematic eqn for rotational motion:
= final angular velocity
= initial angular velocity
= angular acceleration
Now,
Now,
(b) The no. of revolutions is given by:
(c) Tangential component does not depend on instantaneous angular velocity but depends on radius and angular acceleration:
(d) The radial acceleration is given by:
Linear acceleration is given by:
