I'm assuming we're applying the standard Integral form of the calculation of work. The solution is provided in the image.
<em>Answer: </em>tellurium (Te)
<em>atomic number = 52 ,</em>
<em>Number of energy levels = 5;</em>
First energy level = 2
Second energy level = 8
Third energy level = 18
Fourth energy level = 18
Fifth energy level = 6
<em>In this electron configuration, 0uter most electrons are 6.</em>
<span>At the exact instant the blue ball reaches maximum height, it is stationary for that millisecond in time before it begins to fall, therefore its speed is zero. (The other factors listed have no effect on the speed at the moment of maximum height.)</span>
To answer this question, first we take note that the maximum height that can be reached by an object thrown straight up at a certain speed is calculated through the equation,
Hmax = v²sin²θ/2g
where v is the velocity, θ is the angle (in this case, 90°) and g is the gravitational constant. Since all are known except for v, we can then solve for v whichi s the initial velocity of the projectile.
Once we have the value of v, we multiply this by the total time traveled by the projectile to solve for the value of the range (that is the total horizontal distance).
