$\dfrac{2}{3} *n^2-7=17\\\Longrightarrow\ \dfrac{2}{3} *n^2=24\\\Longrightarrow\ n^2=\dfrac{3*24}{2}\\\Longrightarrow\ n^2=36\\\Longrightarrow\ (n-6)(n+6)=0\\\\n=6\ or\ n=-6\\$

8 0

3 years ago

Find a point-slope form for the line with slope 1/5 and passing through the point (-7,-4).

Basile [38]

Answer:

y + 4 = ⅕(x + 7)

Step-by-step explanation:

The "point-slope" form of the equation of a straight line is:

y − y₁ = m(x − x₁)

where m is the slope and (x₁, y₁) is a point on the line.

If m = ⅕ and (x₁, y₁) = (-7, - 4), the point-slope equation is

y + 4 = ⅕(x + 7)

The Figure below shows the graph of your line and a point at (-7, -4).

6 0

3 years ago

Line BC has an equation of a line Y equals 2X +3 and F has an equation of a line Y equals -1/2 x+4 these two equations represent

Masja [62]

Answer:

Lines BC and F represent perpendicular lines

Step-by-step explanation:

we have

Line BC

$y=2x+3$

the slope of the line BC is $m=2$

Line F

$y=-(1/2)x+4$

the slope of the line F is $m=-1/2$

we know that

If two lines are perpendicular, then the product of their slopes is equal to -1

$m1*m2=-1$

we have

$m1=2$ -----> slope line BC

$m2=-1/2$ -----> slope line F

Find the product of their slopes

$(2)(-1/2)=-1$

therefore

Lines BC and F represent perpendicular lines

6 0

3 years ago