1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
il63 [147K]
3 years ago
7

A 2kg object is moving horizontally with a speed of 4m/s 2. How much net force is required t keep the object moving at this spee

d and direction?
Physics
1 answer:
dezoksy [38]3 years ago
8 0
To continue moving at constant speed in a straight line requires NO net force. Zero. Nada. If there IS any net force on the object, then its speed or direction will change.
You might be interested in
Which other team sport basketball is the most like.<br> hi
lana [24]

Answer: mmm... If you mean most like Basketball it's net ball but i don't know much about Basket ball teams

Explanation:

4 0
4 years ago
Two semiconductors are identical except that one has a band gap of 1.2 eV, while the other has a band gap of 1.1 eV. The room te
solong [7]

To solve this problem it is necessary to apply the relationship given by the intrinsic carrier concentration, in each of the phases.

The intrinsic carrier concentration is the number of electrons in the conduction band or the number of holes in the valence band in intrinsic material. This number of carriers depends on the band gap of the material and on the temperature of the material.

In general, this can be written mathematically as

\eta_i = \sqrt{N_cN_v}e^{-\frac{E_g}{2KT}}

Both are identical semiconductor but the difference is band gap which is:

E_{g1} = 1.1eV

n_{i1} = 1*10^{19}m^{-3}

E_{g2} = 1.2eV

T=300K

The ratio between the two phases are given as:

\frac{\eta_{i1}}{\eta_{i2}} = \frac{e^{-\frac{E_{g1}}{2KT}}}{e^{-\frac{E_{g2}}{2KT}}}

\frac{\eta_{i1}}{\eta_{i2}} = e^{\frac{E_{g2}-E_{g1}}{2KT}}

\frac{\eta_{i1}}{\eta_{i2}} =e^{\frac{(1.2-1.1)(1.6*10^{-19})}{2(1.38*10^{-23})(300)}}

\frac{\eta_{i1}}{\eta_{i2}} =e^{-1.932367}

\frac{\eta_{i1}}{\eta_{i2}} =0.145

Therefore the ratio of intrinsic carrier densities for the two materials at room temperature is 0.145

7 0
4 years ago
Youare on a train travelling northat 80.0m/s relative to the ground. The air is still relativetothegroundwhen you hear the whist
AURORKA [14]

To solve this problem we will apply the concepts related to the Doppler effect. This is understood as the change in apparent frequency of a wave produced by the relative movement of the source with respect to its observer. Mathematically this is given as,

f = \frac{v \pm v_r}{v \pm v_s}(f_0)

Here,

v = Speed of the waves in the middle

v_r = Speed of the receiver in relation to the medium (Positive if the receiver is moving towards the transmitter or vice versa)

v_s = Speed of the source with respect to the medium (Positive if the source moves away from the receiver or vice versa)

Our values are given as,

v = 342m/s

f_0 = 262Hz

v_r = 80m/s

f = 350Hz

Replacing,

350 = \frac{342+80}{342-v} (262)

Solving for the velocity of the source,

v = 26.1m/s

Therefore the speed of the other train is 26.1m/s

3 0
3 years ago
A train accelerates from a station with a = 1.841m/s ? Upon reaching a speed of 23.52m/s the train travels at a constant velocit
scZoUnD [109]

Answer:

63.29s

Explanation:

Firstly calculate the time taken to reach 23.52m/s

;use the formula...v = u + at

23.52 = 0 + 1.841t

then obtain...t = 12.78s

Then calculate the time for the last part of the journey...where the train slows down...

use the formula that is above...

0 = 23.52 - 2t...(negative for deceleration)

then obtain....t = 11.76s

Then we know that the total area under the graph of u against t..is equal to 1200m

For the first triangle(first part of the journey...where the train accelerates)

(23.52 × 12.78)÷2 = 150.3m

Then for the constant velocity part...a rectangle...

23.52 × f.....where f represents the time taken by the train having constant velocity.

...= 23.52fm

Then for the last part of the journey...the deceleration part..a triangle

(23.52 × 11.76)÷ 2 = 138.3m

Then....we add all the obtained distances and equate to 1200m so that we can obtain time (f)

138.3 + 150.3 + 23.52f = 1200

where f = 38.75s

Then total time for the whole journey of the train...

38.75 + 11.76 + 12.78

;Ans = 63.29s

3 0
3 years ago
As the period of a wave increases, the frequency increases.
Anarel [89]
See the picture below

3 0
3 years ago
Read 2 more answers
Other questions:
  • A train travels 79 kilometers in 4 hours and then 65 kilometers in 3 hours what is it average speed
    6·1 answer
  • Which of the following is an engineering solution
    10·2 answers
  • At a horse race, all horses started from rest. As soon as the gates were open the horses started to trot. After 300s, Blacky was
    9·1 answer
  • How does the body's arrangement of nerve receptors for touch make the braille system possible
    9·2 answers
  • Can the velocity of a body revese the direction when acceleration is constant?
    15·1 answer
  • How are science and technology the same
    12·1 answer
  • Iron is a solid phase of iron still unknown to science. The only difference between it and ordinary iron is that Iron forms a cr
    9·1 answer
  • Why is a cell phone more likely to break when dropped from a higher height than a lower one?
    11·1 answer
  • Which can give off more heat: a glass full of hot water, or a pitcher full of hot water that has the same temperature?
    9·2 answers
  • to advance in time the evolution of temperature of the atmosphere at any given point in the globe, models calculate the temperat
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!