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3 years ago

Which of the following is an engineering solution

2 answers:

5 0

By "solution" it means a course of action that, once carried out, brings about some desired state of affairs. The use of engineer in this context is as a verb meaning "to arrange or bring about through skillful, artful contrivance."

allochka39001 [22]3 years ago

4 0

Waterless hand cleaner is an engineering solution. What does "the following" mean ?

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The current supplied by a battery as a function of time is ) -(0.64 A)e-/(6.0 hr). What is the total number of electrons transpo

Paha777 [63]

Answer:

The total number of electrons is $8.6\times10^{22}$

(3) is correct option.

Explanation:

Given that,

The current equation is

$I=0.64 e^{\dfrac{-t}{6.0 hr}}$

We know that,

The formula of charge

$q=\int_{0}^{\infty}{I dt}$

$q=\int_{0}^{\infty}{0.64 e^{\dfrac{-t}{6.0 hr}}dt$

$q=0.64\int_{0}^{\infty}{e^{\dfrac{-t}{6.0 hr}}dt$

$q=0.64\int_{0}^{\infty}{e^{\dfrac{-t}{21600}}dt$

$q=0.64(21600e^{\dfrac{-t}{21600}})_{0}^{\infty}$

$q=0.64(0-21600)$

$q=0.64\times21600$

$q=13824\ C$

We need to calculate the number of electron

Using formula of charge

$q=ne$

$n=\dfrac{q}{e}$

$n=\dfrac{13824}{1.6\times10^{-19}}$

$n=8.6\times10^{22}$

Hence, The total number of electrons is $8.6\times10^{22}$

7 0

2 years ago

Which is the second largest planet in our solar system.

hammer [34]

Saturn is the second largest planet in our solar system. At an average distance of 800 million miles (1.3 billion kilometers) from Earth, Saturn is the farthest planet that can be seen without a telescope. Saturn is the sixth planet from the sun. Because Saturn is so far away from the sun, Saturn is considered one of the outer planets. Despite it's large size, Saturn is the least dense planet in our solar system!

6 0

3 years ago

Which of the following statements is an example of weather?

liq [111]

It is 88 degrees in San Diego
Weather is the condition of the atmosphere at a particular place and time

5 0

3 years ago

A car move with uniform acceleration along a straight line pqr .Its speed at p and r are 5m/s and 25m/s respectively if pq:qr is

topjm [15]

Answer:

<em>Answer: Option d.</em>

Explanation:

<u>Accelerated Motion </u>

When an object changes its spped in the same amounts in the same times, the acceleration is constant and its value is

$\displaystyle a=\frac{v_f-v_o}{t}$

Where $v_f, v_o, t$ are the final speed, initial speed, and time taken to change them, respectively

From the above equation we can know

$v_f=v_o+at$

The distance traveled is computed as

$\displaystyle x=v_ot+\frac{at^2}{2}$

The question talks about a car moving in a straight line with constant acceleration. It goes through the points p,q,r such as

$v_p=5\ m/s, v_r=25\ m/s$

The ratio of the distances traveled in each segment is

$\displaystyle \frac{x_1}{x_2}=\frac{1}{2}$

being $x_1$ the distance from p to q and $x_2$ the distance from q to r

It means that

$x_2=2x_1$

From the equation for speed

$v_q=v_p+at_1\ \ \ ..........[1]$

$v_r=v_q+at_2\ \ \ ..........[2]$

Replacing [1] into [2]

$v_r=v_p+at_1+at_2$

$v_r=v_p+a(t_1+t_2)$

Solving for a

$\displaystyle a=\frac{v_r-v_p}{t_1+t_2}\ \ \ .........[3]$

We now write the equation for both distances .

$\displaystyle x_1=v_pt_1+\frac{at_1^2}{2}$

$\displaystyle x_2=v_qt_2+\frac{at_2^2}{2}$

Using [1] again

$\displaystyle x_2=(v_p+at_1)t_2+\frac{at_2^2}{2}$

Since

$x_2=2x_1$

We have

$\displaystyle (v_p+at_1)t_2+\frac{at_2^2}{2}=2\left (v_pt_1+\frac{at_1^2}{2}\right )$

Operating

$\displaystyle v_pt_2+at_1t_2+\frac{at_2^2}{2}=2v_pt_1+at_1^2$

Rearranging

$\displaystyle v_pt_2-2v_pt_1=at_1^2-at_1t_2-\frac{at_2^2}{2}$

Factoring both sides

$\displaystyle v_p(t_2-2t_1)=\frac{a}{2}\left (2t_1^2-2t_1t_2-t_2^2 \right )$

Replacing the equation [3] for a :

$\displaystyle 2v_p(t_2-2t_1)=\frac{v_r-v_p}{t_1+t_2}\left (2t_1^2-2t_1t_2-t_2^2 \right )$

Replacing $v_p=5,\ v_r=25,\ v_r-v_p=20$ , and operating the denominator

$\displaystyle 10(t_2-2t_1)\left (t_1+t_2 \right )=20\left (2t_1^2-2t_1t_2-t_2^2 \right )$

Operating and simplifying, we get a second-degree equation

$\displaystyle t_2^2+t_1t_2-2t_1^2=0$

Factoring

$(t_2-t_1)(t_2+2t_1)=0$

The only positive and valid answer is

$t_2=t_1$

Or equivalently

$\displaystyle \frac{t_1}{t_2}=1$

The option d. is correct

6 0

2 years ago

Nuclear energy can be used to power _______.

Fed [463]

its d. all of the above

5 0

2 years ago