It would be rounded to 2,000 because the number 4 in the hundreds place is under 5 which drops to a 0 instead.
Answer:
7 marigolds will fit in this row
Step-by-step explanation:
Given
Length of the row for planting marigold = 2 yards
Spacing between the flowers = 1/3 yard
The first marigold is planted at 0 yard, the total number of marigold that can be planted is equal to
A 1/3 B 1/3 C 1/3 D 1/3 E 1/3 F 1/3 G
The alphabets represents the marigold flower
Hence, total 7 flowers can be planted
Answer:
a) 0.3495
b) (9.65, 10.35)
Step-by-step explanation:
We are given the following in the question:
Sample mean,
= 10 hours
Sample size, n = 64
Alpha, α = 0.02
Population standard deviation, σ = 1.2 hours
a) Margin of error
Formula
![z_{critical}\dfrac{\sigma}{\sqrt{n}}](https://tex.z-dn.net/?f=z_%7Bcritical%7D%5Cdfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D)
Putting values, we get,
![M.E = (2.33)\dfrac{1.2}{\sqrt{64}} = 0.3495](https://tex.z-dn.net/?f=M.E%20%3D%20%282.33%29%5Cdfrac%7B1.2%7D%7B%5Csqrt%7B64%7D%7D%20%3D%200.3495)
b) the sample mean is 10 hours, then the 98% confidence interval
![\bar{x} \pm M.E](https://tex.z-dn.net/?f=%5Cbar%7Bx%7D%20%5Cpm%20M.E)
Putting the values, we get,
![10\pm 0.3495\\=(9.6505, 10.3495)\\\approx (9.65, 10.35)](https://tex.z-dn.net/?f=10%5Cpm%200.3495%5C%5C%3D%289.6505%2C%2010.3495%29%5C%5C%5Capprox%20%289.65%2C%2010.35%29)
it will take to fill a 10 liter container= 33.3 hours
Answer:
This verified guy is wrong, and all I can say is I resubmitted twice and it's not "He should use the median because it's the center of data" or "He should use the mean because there are no outliers that affect the mean."
Step-by-step explanation:
Actually, it's MEDIAN because there ARE outliers that affect the MEAN. If you take the mean, average, then the $2.5 M house will raise the mean.