3x - 6y = -2
-6y = -3x - 2, divide through by -1
6y = 3x + 2, divide through by 6
y = 3x/6 + 2/6
y = x/2 + 1/3
A -76x+76=-76x+76−76x+76=−76x+76minus, 76, x, plus, 76, equals, minus, 76, x, plus, 76 (Choice B) B 76x+76=-76x+7676x+76=−76x+76
Pie
Answer:
b
Step-by-step explanation:
i could be wrong
(x-9)(x+7)=0
x-9=0 or x+7=0
x=9 or x=-7
:)
If you mean 165x = 31 , X = <span>0.19871794871
if you mean 16*5x = 31 , X = .3875
if you mean 16+5x=31 , X = 3
If you mean 16 -5x=31 , X = -3
Hope one of these is correct.</span>
Given parameters;
Let us solve this problem step by step;
Let us represent Simon's money by S
Kande's money by K
- Simon has more money than Kande
S > K
- if Simon gave Kande K20, they would have the same amount;
if Simon gives $20, his money will be S - 20 lesser;
When Kande receives $20, his money will increase to K + 20
S - 20 = K + 20 ------ (i)
- While if Kande gave Simon $22, Simon would then have twice as much as Kande;
if Kande gave Simon $22, his money will be K - 22
Simon's money, S + 22;
S + 22 = 2(K - 22) ------ (ii)
Now we have set up two equations, let us solve;
S - 20 = K + 20 ---- i
S + 22 = 2(K - 22) ; S + 22 = 2K - 44 ---- ii
So, S - 20 = K + 20
S + 22 = 2K - 44
subtract both equations;
-20 - 22 = (k -2k) + 64
-42 = -k + 64
k = 106
Using equation i, let us find S;
S - 20 = K + 20
S - 20 = 106 + 20
S = 106 + 20 + 20 = 146
Therefore, Kande has $106 and Simon has $146
