Question

Find four consecutive even integers such that if the sum of the first and third was multiplied by 2, the result is 20 less than three times the fourth.

Answer 1

xAnswer:

-10   -8   -6   -4

Step-by-step explanation:

The numbers are  

first =x

second= x+2

third=x+4

4th= x+6

2(x + (x+4)) = 3(x+6)-20

4x+8 = 3x+18–20

4x-3x=18–20–8

x=-10

So the numbers are       -10,           -8,              -6,            -4

                                       first           2nd          3rd             4th

           Check:

         2( -10-6)  = 3(-4) -20

            2(-16) =  -12-20

-32 = -32