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2 years ago

1.3.3 Quiz: Solving Linear Equations

Mathematics

1 answer:

EleoNora [17]2 years ago

8 0

Answer:

A. Add three to both sides. D. Addition property of equality.

Step-by-step explanation:

You can follow PEMDAS to solve this, and I recommend you see your teacher for help.

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When evaluating (6.28x10^12)/(3.14x10^4) what will be the exponent of 10 in the quotient?

alexdok [17]

2*10^8
the exponent would be 8
hope this helps!

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2 years ago

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Dmitry_Shevchenko [17]

It would be the second answer.

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3 years ago

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Solve each equation for the variable given -2(-3v-5)-5v=12(1+v)-2

Ket [755]

Use the photo below

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2 years ago

What is the range of g(x) = 3|x − 1| − 1? A. (-∞, 1] B. [-1, ∞) C. [1, ∞) D. (-∞, ∞)

AVprozaik [17]

Answer:

B. [-1, ∞).

Step-by-step explanation:

g(x) = 3|x − 1| − 1

When x = 1 g(x) = 3(0) - 1 = -1.

As all negative vales of x will give positive values of |x - 1| then g(x) = -1 is its minimum value. The graph will be shaped like a letter V with the vertex at (1,-1).

Therefore the range is [-1, ∞).

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3 years ago

For the month of March in a certain city, 57% of the days are cloudy. Also in the month of March in the same city, 55% of the da

oksian1 [2.3K]

Answer: 0.9649

Step-by-step explanation:

Let A denote the event that the days are cloudy and B denotes the event that the days are rainy.

Given : For the month of March in a certain city, the probability that days are cloudy : $P(A)=0.57$

Also in the month of March in the same city,, the probability that the days are cloudy and rainy : $P(A\cap B)=0.55$

Now by using the conditional probability, the probability that a randomly selected day in March will be rainy if it is cloudy will be :-

$P(B|A)=\dfrac{P(A\cap B)}{P(A)}$

$\Rightarrow\ P(B|A)=\dfrac{0.55}{0.57}\\\\=0.964912280702\approx0.9649\ \ \text{[Rounded to four decimal places.]}$

Hence, the probability that a randomly selected day in March will be rainy if it is cloudy = 0.9649

4 0

3 years ago