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NikAS [45]
3 years ago
9

In a national survey of 1987 adults, 1570 responded that lack of respect and courtesy in American society is a serious problem,

and 1257 indicated that they believe that rudeness is a more serious problem than in past years. Is there convincing evidence that more than three-quarters of U.S. adults believe that rudeness is a worsening problem? Test the relevant hypotheses using a significance level of 0.05. (Round your test statistic to two decimal places and your P-value to four decimal places.)
Mathematics
1 answer:
Alik [6]3 years ago
3 0
<h2>Answer with explanation:</h2>

As per given , we  have

H_0: p\leq\dfrac{3}{4}\\\\H_a: p>\dfrac{3}{4}

Since , alternative hypothesis is right tailed, so the test is a right tailed test.

n= 1987

Proportion of adults believe that rudeness is a worsening problem : p=\dfrac{1257}{1987}\approx 0.6326

Test statistic : z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}

z=\dfrac{ 0.6326-0.75}{\sqrt{\dfrac{0.75(1-0.75)}{1987}}}=-12.09

(since , the normal curve takes values of z from -7 to 7, so we use critical value to draw conclusion.)

The critical value for a significance level of 0.005= 1.645

Since , absolute test statistic value (12.09) is greater than the critical value (1.645), it means there is statistical significance and so we reject the null hypothesis.

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Consider the following.
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Answer:

Anything in the form x = pi+k*pi, for any integer k

These are not removable discontinuities.

============================================================

Explanation:

Recall that tan(x) = sin(x)/cos(x).

The discontinuities occur whenever cos(x) is equal to zero.

Solving cos(x) = 0 will yield the locations when we have discontinuities.

This all applies to tan(x), but we want to work with tan(x/2) instead.

Simply replace x with x/2 and solve for x like so

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x/2 = arccos(0)

x/2 = (pi/2) + 2pi*k or x/2 = (-pi/2) + 2pi*k

x = pi + 4pi*k   or    x = -pi + 4pi*k

Where k is any integer.

If we make a table of some example k values, then we'll find that we could get the following outputs:

  • x = -3pi
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and so on. These are the odd multiples of pi.

So we can effectively condense those x equations into the single equation x = pi+k*pi

That equation is the same as x = (k+1)pi

The graph is below. It shows we have jump discontinuities. These are <u>not</u> removable discontinuities (since we're not removing a single point).

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