Question

Can someone please help???

Answer 1

Proof (reasons are given in brackets):

Consider $\triangle ABC$, $\triangle EDC$:

$\overline B \overline C = \overline D \overline C$ (given)

$\angle BCA = \angle DCE$ (vertically opposite angles are equal)

$\overline A \overline C = \overline E \overline C$ (given)

$\therefore \triangle ABC \cong \triangle EDC$ (SAS)

Hope this helps :)