Answer:
D
Step-by-step explanation:
I have answers to whole packet:
1.D
2.A
3.C
4.D
5.C
6.D
7.A
8.C
9.A
10.B
11.A
12.A
13.A
14.B
15.A
16.B
17.A
18.A
19.B
20.C
21.A
22.A
23.D
24.B
Answer: 7983.65
Step-by-step explanation:
Equation:
A = P ( 1 + r/n)^nt
R : r/100 : 3% : 0.0.3
A = 6670( 1 + ( 0.03/12) : ^12(16)
A: 6670( 1 + 0.0025)^(74)
Put this on calculator
A = 7983.65
Hope this help.
36/b-3=0
36/b=3
3b=36
b=36/3
b=12
Answer:
The minimum sample size is ![n = 2123](https://tex.z-dn.net/?f=n%20%20%3D%202123)
Step-by-step explanation:
From the question we are told that
The margin of error is ![E = 0.028](https://tex.z-dn.net/?f=E%20%3D%20%200.028)
Given that the confidence level is 99% then the level of significance is evaluated as
![\alpha = 100 - 99](https://tex.z-dn.net/?f=%5Calpha%20%20%3D%20%20100%20-%20%2099)
![\alpha = 1 \%](https://tex.z-dn.net/?f=%5Calpha%20%20%3D%20%201%20%5C%25)
![\alpha =0.01](https://tex.z-dn.net/?f=%5Calpha%20%20%3D0.01)
Next we obtain the critical value of
from the normal distribution table
The value is ![Z_{\frac{ \alpha }{2} } = 2.58](https://tex.z-dn.net/?f=Z_%7B%5Cfrac%7B%20%5Calpha%20%7D%7B2%7D%20%7D%20%3D%20%202.58)
Now let assume that the sample proportion is ![\r p = 0.5](https://tex.z-dn.net/?f=%5Cr%20p%20%20%3D%20%200.5)
hence ![\r q = 1 - \r p](https://tex.z-dn.net/?f=%5Cr%20q%20%3D%20%201%20-%20%5Cr%20p)
=> ![\r q = 0.50](https://tex.z-dn.net/?f=%5Cr%20q%20%3D%20%200.50)
Generally the sample size is mathematically represented as
![n =[ \frac{Z_{\frac{ \alpha }{2} }}{ E} ]^2 * \r p * \r q](https://tex.z-dn.net/?f=n%20%20%3D%5B%20%5Cfrac%7BZ_%7B%5Cfrac%7B%20%5Calpha%20%7D%7B2%7D%20%7D%7D%7B%20E%7D%20%5D%5E2%20%20%2A%20%20%5Cr%20p%20%2A%20%20%5Cr%20q)
![n =[ \frac{2.58}{ 0.028} ]^2 * 0.5 * 0.5](https://tex.z-dn.net/?f=n%20%20%3D%5B%20%5Cfrac%7B2.58%7D%7B%200.028%7D%20%5D%5E2%20%20%2A%20%200.5%20%2A%20%200.5)
![n = 2123](https://tex.z-dn.net/?f=n%20%20%3D%202123)