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3 years ago

HELP! Evaluate the expression below for s = 4 and t = 6. 4st² – s²

Mathematics

2 answers:

Leto [7]3 years ago

6 0

Answer:

560

Step-by-step explanation:

joja [24]3 years ago

6 0

Answer:

560

Step-by-step explanation:

substitute "s" and "t" into the equation:

4(4)(6)^2-(4)^2

when you solve this according to the order of operations, you will get 560

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. Mallorie has $5.50 in her wallet. If this is 10% of her monthly allowance, what is her

Zinaida [17]

Answer:

Hello!!

If Mallorie has $5.50 in her wallet. If this is 10% of her monthly allowance, her monthly allowance is $50.

Step-by-step explanation:

$5.50$ ÷ $10=0.55$ round decimal two places to the right

Hope this helps!!

7 0

2 years ago

Min is about to roll a six-sided number cube. What is the probability that she will roll an even number? A) 1 4 B) 1 3 C) 1 2 D)

Irina-Kira [14]

P(e)=number of evens/number of numbers :)

P(e)=3/6=1/2

8 0

3 years ago

Read 2 more answers

Help me out please!!!!!!!

Dimas [21]

Answer: The missing side is 6mm.

Step-by-step explanation: For 18mm to drop to 12mm, it dropped 6mm. Therefore, the missing side was 12mm, and if you drop 6mm, you get 6mm.

3 0

3 years ago

An airplane travels 6111 kilometers against the wind in 9 hours and 7911 kilometers with the wind in the same amount of time. Wh

natima [27]

Answer:

Speed of the plane in still air: $779\; {\rm km \cdot h^{-1}}$ .

Windspeed: $100\; {\rm km \cdot h^{-1}}$ .

Step-by-step explanation:

Assume that $x\; {\rm km \cdot h^{-1}}$ is the speed of the plane in still air, and that $y\; {\rm km \cdot h^{-1}}$ is the speed of the wind.

When the plane is travelling against wind, the ground speed of this plane (speed of the plane relative to the ground) would be $(x - y)\; {\rm km \cdot h^{-1}}$ .
When this plane is travelling in the same direction as the wind, the ground speed of this plane would be $(x + y)\; {\rm km \cdot h^{-1}}$ .

The question states that when going against the wind ( $v = (x - y)\; {\rm km \cdot h^{-1}}$ ,) the plane travels $6111\; {\rm km}$ in $9\; {\rm h}$ . Hence, $9\, (x - y) = 6111$ .

Similarly, since the plane travels $7911\; {\rm km}$ in $9\; {\rm h}$ when travelling in the same direction as the wind ( $v = (x + y)\; {\rm km \cdot h^{-1}}$ ,) $9\, (x + y) = 7911$ .

Add the two equations to eliminate $y$ . Subtract the second equation from the first to eliminate $x$ . Solve this system of equations for $x$ and $y$ : $x = 779$ and $y = 100$ .

Hence, the speed of this plane in still air would be $779\; {\rm km \cdot h^{-1}}$ , whereas the speed of the wind would be $100\; {\rm km \cdot h^{-1}}$ .

3 0

1 year ago

Find the 37th term of 352,345,338

Mariulka [41]

Answer:

$a_{37}=100$

Step-by-step explanation:

Given that,

A sequence 352,345,338.

First term = 352

Common difference = 345-352 = -7

We need to find the 37th term of the sequence.

The nth term of an AP is given by :

$a_n=a+(n-1)d\\\\a_{37}=352+36\times (-7)\\\\a_{37}=100$

So, the 37th term of the sequence is 100.

8 0

3 years ago