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Soloha48 [4]
2 years ago
14

Denominator of the fraction

Mathematics
1 answer:
Law Incorporation [45]2 years ago
7 0

Answer:

Denominator for 2/5 is 5, and denominator for 13/16 is 16.

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write a system of linear equations that has only one solution. solve the system of equations in two ways.
Iteru [2.4K]
X + 5y = 1 . . . . (1)
8x - 2y = 3 . . . .(2)
Solution 1.
From (1), x = 1 - 5y
substituting for x in (2), we have:
8(1 - 5y) - 2y = 3
8 - 40y - 2y = 3
8 - 42y = 3
42y = 5
y = 5/42
x = 1 - 5(5/42) = 1 - 25/42 = 17/42.

Solution 2.
Multiply (1) by 8, to get:
8x + 40y = 8 . . . . . (3)
(3) - (2) = 40y - (-2y) = 8 - 3
42y = 5
y = 5/42
substitute for y into (3), to get:
8x + 40(5/42) = 8
8x + 100/21 = 8
8x = 8 - 100/21 = 68/21
x = (68/21)/8 = 17/42
7 0
2 years ago
Area and percent . ​
siniylev [52]

Answer:

a. 61.92 in²

b. 21.396 ≈ 21.4%

c. $4.71

Step-by-step explanation:

a. Amount of waste = area of rectangular piece of stock - area of two identical circles cut out

Area of rectangular piece of stock = 24 in × 12 in = 288 in²

Area of the two circles = 2(πr²)

Use 3.14 as π

radius = ½*12 = 6

Area of two circles = 2(3.14*6²) = 226.08 in²

Amount of waste = 288 - 226.08 = 61.92 in²

b. % of the original stock wasted = amount of waste ÷ original stock × 100

= 61.92/288 × 100 = 6,162/288 = 21.396 ≈ 21.4%

c. 288 in² of the piece of stock costs $12.00,

Each cut-out circle of 113.04 in² (226.08/2) will cost = (12*113.04)/288

= 1,356.48/288 = $4.71.

3 0
3 years ago
Which expression is equivalent to (-4y - x) - (3y - 9x)
WINSTONCH [101]

Answer: -7y+8x

Step-by-step explanation: I assume you mean to simplify

Step 1: Remove parentheses : -4y - x - (3y - 9x)

Step 2: -(3y - 9x) = -3y + 9x

Step 3: Simplify: -4y - x - 3y +9x

Step 4: Answer: -7y+8x

4 0
2 years ago
An ant can run an inch per second. How long will it take the same ant to run a foot?​
RideAnS [48]
12 seconds bc 12 in in a foor
8 0
3 years ago
Read 2 more answers
Given the following definition, compute Q(5). Q(n) = 0 if n = 0 2 if n = 1 4 if n = 2 Q(n − 1) + Q(n − 2) + Q(n − 3) if n > 2
aalyn [17]
We have 
Q(0)=0\\
Q(1)=2\\
Q(2)=4
and Q(n)=Q(n-1)+Q(n-2)+Q(n-3)\mbox{ when } n\ \textgreater \ 2.
So 
Q(3)=Q(2)+Q(1)+Q(0)=4+2+0=6\\
Q(4)=Q(3)+Q(2)+Q(1)=6+4+2=12\\
Q(5)=Q(4)+Q(3)+Q(2)=12+6+4=22.

3 0
2 years ago
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