Answer:
A mutation near the middle of a gene changes the DNA to the following nucleotides: ATT. What kind of mutation occurred in this situation?
missense mutation
Explanation:
Answer:
ATP synthase would be unable to produce ATP
Explanation:
ATP synthase depends on the proton gradient in the intermembrane space to enable it to produce ATP. As a consequence of this, the toxin will make it inactive. Oxidative phosphorylation is now inhibited in this case, as opposed to substrate-level phosphorylation.
Pyruvate is a product of glycolysis, and it will not be affected by a toxin. NADH is very important in the establishing of a proton gradient, so it is expected that it would be unable to be oxidized due to the toxin. Protons produced in the conversion of NADH to NAD+ actually establish the proton gradient. If the gradient is absent, NADH is then not likely to be oxidized.
There are choices for this question namely:
a. What is your name and where do you live?
b. How much poison did you swallow?
c. How long have you been feeling this way?
<span>d. What have you recently had to eat or drink?
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The correct answer is "what have you recently had to eat or drink". This will confirm the suspicion by first ruling out potential reactive foods or drinks that may have caused a similar reaction (i.e. allergic reactions). If that is ruled out, then the probing about the history of intake of poison will come next in the interview.
C. From carbon dioxide in the atmosphere
Answer:
The correct answer is- C. double or single-stranded DNA or double or single-stranded RNA.
Explanation:
All the viruses are intracellular parasites which means they obtain their nutrition from their host. Viruses do not have cellular level of organization. They only have their nucleic acid which is surrounded by a protein coat called a capsid.
The nucleic acid in viruses can be of different types. It can be single or double-stranded DNA or single or double-stranded RNA. Their genome can be linear or circular. They inject their genetic material in their host and introduce it in the host genome. Therefore the correct answer is C.