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3 years ago

Use the quadratic formula to solve the equation, which has one solution. y2+2y+1=0

Mathematics

1 answer:

Blababa [14]3 years ago

3 0

Answer :y=−1

Step-by-step explanation:

y2+2y+1=0

Step 1: Factor left side of equation.

(y+1)(y+1)=0

Step 2: Set factors equal to 0.

y+1=0 or y+1=0

y=−1

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Rather than carrying out IBP several times, let's establish a more general result. Let

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One round of IBP, setting

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gives

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$I(5)=x^5e^x-5I(4)$

$I(5)=x^5e^x-5(x^4e^x-4I(3))=(x-5)x^4e^x+20I(3)$

$I(5)=(x-5)x^4e^x+20(x^3e^x-3I(2))=(x^2-5x+20)x^3e^x-60I(2)$

$I(5)=(x^2-5x+20)x^3e^x-60(x^2e^x-2I(1))=(x^3-5x^2+20x-60)x^2e^x+120I(1)$

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