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kvv77 [185]
2 years ago
7

Ellen can purchase 5 apples for $1.75. How many apples can she get for $1?

Mathematics
1 answer:
Romashka-Z-Leto [24]2 years ago
6 0

Answer:

2 apples

Step-by-step explanation:

  1. 1.75 ÷ 5 = 0.35
  2. 1 ÷ 0.35 = 2.85
  3. 2.85 rounded = 2

I hope this helps!

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Step-by-step explanation:

8 0
3 years ago
In the game fortrix, a player can earn 3, 7, or 11 points on a turn. how many different scores are possible for a single player
BARSIC [14]
18 or 3 * 6 because to find out how many possible contengencys you muktiplyy the factors.
3 0
3 years ago
Determine the future value of a $25000 investment at an annual rate of 4.85% compounded quarterly for 6 years.
Nutka1998 [239]
 = $ 32,275.00

Equation:
A = P(1 + rt)
Calculation:
First, converting R percent to r a decimal
r = R/100 = 4.85%/100 = 0.0485 per year,
putting time into years for simplicity,
24 quarters ÷ 4 quarters/year = 6 years,
then, solving our equation

A = 25000(1 + (0.0485 × 6)) = 32275 
A = $ 32,275.00

The total amount accrued, principal plus interest,
from simple interest on a principal of $ 25,000.00
at a rate of 4.85% per year
for 6 years (24 quarters) is $ 32,275.00.
3 0
3 years ago
Two ships leave a harbor together, traveling on courses that have an angle of 135°40' between them. If they each travel 402 mile
mario62 [17]

Answer:

Therefore they are 734.106 miles apart.

Step-by-step explanation:

Given that ,

Two ships have a harbor together. The angle between two ships  is  135°40'. Each of two ships travel 402 miles.

It forms a isosceles triangle whose two sides are 402 miles and one angle is 135°40'. Since it is isosceles triangle then other two angles of the triangle is equal.

Let ∠B= 135°40', and AB = 402 miles , BC =  402 miles

Then the distance between the ships = AC

We know

The sum of all angles = 180°

⇒∠A+∠B+∠C=180°

⇒∠A+135°40'+∠C=180°

⇒2∠A= 180°- 135°40'      [ since ∠A=∠C]

⇒2∠A=44°60'

⇒∠A= 22°30'

Again we know that,

\frac{AB}{sin\angle C}=\frac{BC}{sin \angle A}=\frac{AC}{sin \angle B}

Taking last two ratio,

\frac{BC}{sin \angle A}=\frac{AC}{sin \angle B}

Putting the value of BC , AC ,∠A,∠B

\frac{402}{sin 22^\circ30'}=\frac{AC}{sin 135^\circ40'}

\Rightarrow AC=\frac{402 \times sin135^\circ40'}{sin 22^\circ30'}

         ≈734.106 miles

Therefore they are 734.106 miles apart.

3 0
3 years ago
Plizz help me out on this oneee
Kobotan [32]
There are 30 students all together, and 4 of them are Freshman girls (Freshwomen ?). So the probability that one randomly chosen student is a Female Frosh is 4/30 = 2/15.
8 0
3 years ago
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