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Neporo4naja [7]
3 years ago
11

The table shows the time Merrida spent driving and the number of miles she drove. She drove the same number of miles each hour.

Mathematics
2 answers:
Bumek [7]3 years ago
8 0

Answer: (B)

Step-by-step explanation: 35 miles per hour. :)

Bezzdna [24]3 years ago
5 0
Use the time ÷ the mileage. 140÷4, 175÷5, 210÷6 all equal 35 miles per hour
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AC has endpoints<br> A(3,7) and C(6,11).<br> Find AB if B is the<br> midpoint of AC.
faltersainse [42]

Answer:

d=2.5

Step-by-step explanation:

first find the coordinate of B(mid point of AC):A(3,7) C(6,11)

d=√(6-3)²+(11-7)²

d=√3²+4²

d=√9+16=√25=5

since B is the mid point : d/2=5/2=2.5

<h2>Another way :</h2>

B(x1+x2/2 , y1+y2/2)   , x1=3 , x2=6, y1=7, y2=11

B(9/2,18/2)

B(9/2,9)

Find AB : the length or distance between 2 points:

d=√(x2-x1)²+(y2-y1)²

d=√(3-9/2)²+(7-9)²

d=√(-3/2)²+(-2)²

d=√1.5²+4

d=√6.25

d=2.5

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Which is the equation of a line that has a slope of Negative two-thirds and passes through point (–3, –1)?
weqwewe [10]

Answer:

Y=2/3x+1

Step-by-step explanation:

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Find X and Y and show please show calculations
torisob [31]

Answer:

Y = 90

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Step-by-step explanation:

Y is on a straight line. The sum of the angles on a straight line is 180.

The only other angle (that is marked) on this straight line, is a 90 degree one. So, <y + 90 = 180.

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Step-by-step explanation:

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Read 2 more answers
Make n the subject of the formula
kogti [31]

Answer:

\mathsf{ \frac{m + 21}{5} = n }

Step-by-step explanation:

To make "n" the subject of the formula, rearrange the formula so it begins with " n = "

To isolate the variable "n", you need to inverse the other terms on that side of the equation where "n" really is.

=> m = 5n - 21

  • <em>there's</em><em> </em><em>a</em><em> </em><em>"</em><em>-21</em><em>"</em><em> </em><em>next</em><em> </em><em>to</em><em> </em><em>"</em><em>5n</em><em>"</em><em>,</em><em> </em><em>inverse</em><em> </em><em>of</em><em> </em><em>subtraction</em><em> </em><em>is</em><em> </em><em>addition</em><em>,</em><em> </em><em>so</em><em> </em><em>add</em><em> </em><em>21</em><em> </em><em>on</em><em> </em><em>both</em><em> </em><em>sides</em><em> </em><em>of</em><em> </em><em>the</em><em> </em><em>equation</em><em>.</em><em> </em>

=> m + 21 = 5n <u>-</u> <u>21</u> + <u>21</u>

=> m+ 21 = 5n

  • <em>There's</em><em> </em><em>also</em><em> </em><em>a</em><em> </em><em>5</em><em> </em><em>attached</em><em> </em><em>to</em><em> </em><em>n</em><em>,</em><em> </em><em>that</em><em> </em><em>means</em><em> </em><em>the</em><em> </em><em>multiplication</em><em> </em><em>of</em><em> </em><em>n</em><em> </em><em>with</em><em> </em><em>5</em><em>,</em><em> </em><em>the</em><em> </em><em>inverse</em><em> </em><em>of</em><em> </em><em>multiplication</em><em> </em><em>is</em><em> </em><em>division</em><em>,</em><em> </em><em>so</em><em> </em><em>dividing</em><em> </em><em>both</em><em> </em><em>sides</em><em> </em><em>of</em><em> </em><em>the</em><em> </em><em>equation</em><em> </em><em>by</em><em> </em><em>5</em>

<em>\mathsf{ \frac{m + 21}{5} = n }</em>

3 0
3 years ago
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