The answer to the question
Answer:
140
Step-by-step explanation:
We have been given two fractions 
and 
. We are asked to find the least common denominator of both fractions.
To find the least common denominator of both fractions, we will find least common multiple of 20 and 28.
Prime factorization of 20: 
Prime factorization of 28: 
Least common multiple of 20 and 28 would be: 
.
Therefore, the least common denominator of both fractions would be 140.
4tan^(2)x-((4)/(cotx))+sinxcscx
Multiply -1 by the (4)/(cotx) inside the parentheses.
4tan^(2)x-(4)/(cotx)+sinxcscx
To add fractions, the denominators must be equal. The denominators can be made equal by finding the least common denominator (LCD). In this case, the LCD is cotx. Next, multiply each fraction by a factor of 1 that will create the LCD in each of the fractions.
4tan^(2)x*(cotx)/(cotx)-(4)/(cotx)+sin...
Complete the multiplication to produce a denominator of cotx in each expression.
(4tan^(2)xcotx)/(cotx)-(4)/(cotx)+(cot...
Combine the numerators of all expressions that have common denominators.
<span>
(4tan^(2)xcotx-4+cotxsinxcscx)/(cotx)</span>
The 21 part repeats
it can be represented as 21/99
it's rational
If you represent the problem in a diagram, you will form a triangle with 3 known length of the sides. When you are given all sides, and you are asked to find an angle, you can use the cosine law.
b^2 = a^2 + c^2 - 2ac*cosB
1.4^2 = 1.9^2 + 1^2 - 2(1.9*1)(cosB)
B = 45.78°
