Answer:
Heyy
Step-by-step explanation:
△ABC is a right angled triangle and right angle at B
sinA=
AC
BC
, cosA=
AC
AB
⟹sinA+cosA=
AC
BC
+
AC
AB
=
AC
BC+AB
[We know that sum of two sides of a triangle is greater than the third side]
⟹sinA+cosA>
AC
AC
=1
Hence, sinA+cosA>1
0.925x^2 - 4x + 20 = -1.125x^2 + 6x + 40 (at break even point)
2.05x^2 - 10x - 20 = 0
x = [ - (-10) +/- sqrt(100 - 4*2.05*-20) / (2*2.05)
x = 6.40, -1.52 Ignore the negative
Answer is 6.40
.00347222222 . Go Brainly!
Your answer is 1.3249751e+19
The answer would be the first image.
Step-by-step explanation:
From context, it appears that to be circumscribed is to be drawn about; thus the square circumscribed about the circle is the first graph.