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Tems11 [23]
3 years ago
7

For a group of 50 people, assuming that each person is equally likely to have a birthday on each of 365 days in the year, comput

e
(a) The expected number of days of the year that are birthdays of exactly 3 people:
Mathematics
1 answer:
kramer3 years ago
6 0

Answer:

0.0177 days

Step-by-step explanation:

Solution:-

- The group has n = 50 people

- Each person is equally likely to have a birthday on each of 365 days in the year.

- The probability of success p = 1 / 365

- The probability of failure q = (1 - 1/365)

- We will denote random variable X as a given day has k number of birthdays.

- X follows binomial distribution:

                            X ~ Bi ( 50 , 1/365)

- The probability that there would be 3 birthdays on a day would be:

                           P ( X = 3 ) = 50C3 ( 1 / 365)^3 * ( 1 - 1/365)^47

                           P ( X = 3 ) = 0.00035

- The expected number of days for exactly three people to have same birth date:

                          E( X = 3 ) = P (X=3)*n = 0.00035*50 = 0.0177 days

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Step-by-step explanation:

From the given right-angle triangle

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x = 1

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y=\frac{\sqrt{3}}{2}       ∵  \sin \left(60^{\circ \:}\right)=\frac{\sqrt{3}}{2}

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Summary:

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