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Kisachek [45]
3 years ago
14

Can someone please answer this question fast ? the question is in the picture down

Mathematics
2 answers:
hoa [83]3 years ago
8 0

Answer:

Always

Step-by-step explanation:

I am not drawing a scech for you have a brain

Lena [83]3 years ago
4 0

Answer:

Yes, Always

Step-by-step explanation:

If M is the midpoint of line KL, then M, K, and L are collinear.

As you notice in the diagram, to be collinear means part of the same line.

please mark brainliest

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Help please asap PLEASE TELL ME THE WORKING AS WELL.​
DanielleElmas [232]

Answer:

a = 9 / 7

step by step explanation:

9 / - a + 15 = 8

Determined the defined range

9 / ( - a ) + 15 = 8 , a ≠ 0

subtract 15 from each side

9 / - a + 15 - 15 = 8 - 15

calculate the difference

9 / - a = - 7

multiply both side of equation by - a

9 / - a × - a = - 7 × - a

9 = 7 a

divide each side by of equation by -7

9 / 7 = 7 a / 7

9 / 7 = a

swap the side of equation . ( optional )

a = 9 / 7

6 0
3 years ago
Read 2 more answers
Which of these is a binomial? O A. x + 2y2 - 7 O B. ab O C. 5xy O D. 2x3 - 7y3​
Lemur [1.5K]

Answer:

D

Step-by-step explanation:

2 terms

8 0
3 years ago
Calculate two iterations of Newton's Method for the function using the given initial guess. (Round your answers to four decimal
pickupchik [31]

Answer:

The first and second iteration of Newton's Method are 3 and \frac{11}{6}.

Step-by-step explanation:

The Newton's Method is a multi-step numerical method for continuous diffentiable function of the form f(x) = 0 based on the following formula:

x_{i+1} = x_{i} -\frac{f(x_{i})}{f'(x_{i})}

Where:

x_{i} - i-th Approximation, dimensionless.

x_{i+1} - (i+1)-th Approximation, dimensionless.

f(x_{i}) - Function evaluated at i-th Approximation, dimensionless.

f'(x_{i}) - First derivative evaluated at (i+1)-th Approximation, dimensionless.

Let be f(x) = x^{2}-8 and f'(x) = 2\cdot x, the resultant expression is:

x_{i+1} = x_{i} -\frac{x_{i}^{2}-8}{2\cdot x_{i}}

First iteration: (x_{1} = 2)

x_{2} = 2-\frac{2^{2}-8}{2\cdot (2)}

x_{2} = 2 + \frac{4}{4}

x_{2} = 3

Second iteration: (x_{2} = 3)

x_{3} = 3-\frac{3^{2}-8}{2\cdot (3)}

x_{3} = 2 - \frac{1}{6}

x_{3} = \frac{11}{6}

7 0
4 years ago
Helppp PLS
Alik [6]
The answer to 1. Is c

The answer to 2. Is 176
8 0
2 years ago
the length of a rectangle is three less than twice its width. If the perimeter is 48, find the length.
Alisiya [41]

length = 15

let the width = w then length = 2w - 3

Perimeter = 2(length + width)

                = 2(2w - 3 + w) = 2( 3w - 3) = 6w - 6 = 48

hence 6w = 48 + 6 = 54 ⇒ w =\frac{54}{6}= 9

Thus length = 2w - 3 = (2× 9) - 3 = 18 - 3 = 15


3 0
3 years ago
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