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2 years ago

Can someone please answer this question fast ? the question is in the picture down

Mathematics

2 answers:

hoa [83]2 years ago

8 0

Answer:

Always

Step-by-step explanation:

I am not drawing a scech for you have a brain

Lena [83]2 years ago

4 0

Answer:

Yes, Always

Step-by-step explanation:

If M is the midpoint of line KL, then M, K, and L are collinear.

As you notice in the diagram, to be collinear means part of the same line.

please mark brainliest

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<img src="https://tex.z-dn.net/?f=%20%7Bx%7D%5E%7B2%7D%20%3D%20%20-%205x" id="TexFormula1" title=" {x}^{2} = - 5x" alt=" {x}^{2

aliina [53]

Answer:

x(x + 5) = 0

Step-by-step explanation:

x² = - 5x

x² + 5x = 0

x(x + 5) = 0

hope it's helpful

3 0

2 years ago

Read 2 more answers

What are the formulas for exponential growth and decay?

fiasKO [112]

Answer: The formula for exponential growth is y = a(1 + r)^x, and the formula for exponential decay is y = a(1 - r)^x, with r being the rate of growth/decay. :)

5 0

3 years ago

Read 2 more answers

Let f(x)=x^2+2x+3 . What is the average rate of change for the quadratic function from x=−2 to x = 5?

miskamm [114]

To find the average rate of change of given function f(x) on a given interval (a,b):

Find f(b)-f(a), b-a, and then divide your result for f(b)-f(a) by your result for b-a:

f(b) - f(a)
------------
b-a

Here your function is f(x) = x^2 - 2x + 3. Substituting b=5 and a=-2,
f(5) = 5^2 -2(5)+3 =? and f(-2) = (-2)^2 - 2(-2) + 3 = ?

Calculate f(5) - [ f(-2) ]
------------------ using your results, above.
5 - [-2]

Your answer to this, if done correctly, is the "average rate of change of the function f(x) = x^2+2x+3 on the interval [-2,5]."

5 0

3 years ago

How do i solve 426 to the nearest ten

Dmitry [639]

Youll need to provide more information

4 0

3 years ago

Read 2 more answers

Starting in the 1970s, medical technology allowed babies with very low birth weight (VLBW, less than 1500 grams, about 3.3 pound

cluponka [151]

Answer:

The test statistic value using the VLBW babies as group 1 is z=-2.76±0.01 and the P-value for the test (±0.0001) is 0.0030.

Step-by-step explanation:

This is a hypothesis test for the difference between proportions.

The claim is that the proportion of persons with normal birth weight that graduates from high school is significantly greater than the proportion of persons with very low birth weight that graduates from high school.

Then, the null and alternative hypothesis are:

$H_0: \pi_1-\pi_2=0\\\\H_a:\pi_1-\pi_2> 0$

The significance level is 0.05.

The sample 1 (VLBW group), of size n1=244 has a proportion of p1=0.77049.

$p_1=X_1/n_1=188/244=0.77049$

The sample 2 (control group), of size n2=247 has a proportion of p2=0.79757.

$p_2=X_2/n_2=197/247=0.79757$

The difference between proportions is (p1-p2)=-0.02708.

$p_d=p_1-p_2=0.77049-0.79757=-0.02708$

The pooled proportion, needed to calculate the standard error, is:

$p=\dfrac{X_1+X_2}{n_1+n_2}=\dfrac{188+197}{244+247}=\dfrac{385}{491}=0.988$

The estimated standard error of the difference between means is computed using the formula:

$s_{p1-p2}=\sqrt{\dfrac{p(1-p)}{n_1}+\dfrac{p(1-p)}{n_2}}=\sqrt{\dfrac{0.988*0.012}{244}+\dfrac{0.988*0.012}{247}}\\\\\\s_{p1-p2}=\sqrt{0.00005+0.00005}=\sqrt{0.0001}=0.0098$

Then, we can calculate the z-statistic as:

$z=\dfrac{p_d-(\pi_1-\pi_2)}{s_{p1-p2}}=\dfrac{-0.02708-0}{0.0098}=\dfrac{-0.02708}{0.0098}=-2.76$

This test is a left-tailed test, so the P-value for this test is calculated as (using a z-table):

$P-value=P(t$

As the P-value (0.0030) is smaller than the significance level (0.05), the effect issignificant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the proportion of persons with normal birth weight that graduates from high school is significantly greater than the proportion of persons with very low birth weight that graduates from high school.

3 0

3 years ago