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kap26 [50]
4 years ago
5

What is the range of the below relation? {(3,-1), (-1,-4), (-4,6), (6,-1)}

Mathematics
1 answer:
tamaranim1 [39]4 years ago
7 0
The answer is 3 negative 2
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Lateral surface area
ivann1987 [24]
The answer is going to be <span>181.121506177483. hope that helped</span>
3 0
3 years ago
The average score of this quiz is 24 points with a standard deviation of 1.5 points. What is the probability that someone scored
navik [9.2K]

Answer:

8.08 %

Step-by-step explanation:

Let us denote : X= score X follows a normal distribution with mean =24 and standard deviation =1.5

Step 2

The probability that someone scored 21.9 or less is :

\mathrm{P}(\mathrm{X} \leq 21.9)

=\mathrm{P}\left(\mathrm{Z} \leq \frac{21.9-24}{1.5}\right)

=\mathrm{P}(\mathrm{Z} \leq-1.4)

=0.0808

=8.08%

Answer : 8.08 %

7 0
3 years ago
3/4 + 1/2=
Bas_tet [7]

Answer:

Okay so,

Step-by-step explanation:

the first one is

1.25 or 1 \frac{1}{4}

second one is

0.5 or \frac{1}{2}

the third one is

i'm not sure what the question is

the fourth one is

i'm not sure what the question is. Are you dividing?

the fifth one is

153.18

the sixth one is

1010.25

the seventh one is

4.066362

the eight one is

i'm not sure what the question is

Can you make me brainliest please

6 0
3 years ago
Read 2 more answers
The sum of three numbers in <br> g.p. is 21 and the sum of their squares is 189. find the numbers.
sashaice [31]
Let the three gp be a, ar and ar^2
a + ar + ar^2 = 21 => a(1 + r + r^2) = 21 . . . (1)
a^2 + a^2r^2 + a^2r^4 = 189 => a^2(1 + r^2 + r^4) = 189 . . . (2)
squaring (1) gives
a^2(1 + r + r^2)^2 = 441 . . . (3)
(3) ÷ (2) => (1 + r + r^2)^2 / (1 + r^2 + r^4) = 441/189 = 7/3
3(1 + r + r^2)^2 = 7(1 + r^2 + r^4)
3(r^4 + 2r^3 + 3r^2 + 2r + 1) = 7(1 + r^2 + r^4)
3r^4 + 6r^3 + 9r^2 + 6r + 3 = 7 + 7r^2 + 7r^4
4r^4 - 6r^3 - 2r^2 - 6r + 4 = 0
r = 1/2 or r = 2
From (1), a = 21/(1 + r + r^2)
When r = 2:
a = 21/(1 + 2 + 4) = 21/7 = 3
Therefore, the numbers are 3, 6 and 12.
3 0
3 years ago
You have been asked to design a can shaped like right circular cylinder that can hold a volume of 432π-cm3. What dimensions of t
rosijanka [135]

Answer:

Height = 12cm

Radius = 6cm

Step-by-step explanation:

Given

Represent volume with v, height with h and radius with r

V = 432\pi

Required

Determine the values of h and r that uses the least amount of material

Volume is calculated as:

V = \pi r^2h\\

Substitute 432π for V

432\pi = \pi r^2h

Divide through by π

432 = r^2h

Make h the subject:

h = \frac{432}{r^2}

Surface Area (A) of a cylinder is calculated as thus:

A=2\pi rh+2\pi r^2

Substitute \frac{432}{r^2} for h in A=2\pi rh+2\pi r^2

A=2\pi r(\frac{432}{r^2})+2\pi r^2

A=2\pi (\frac{432}{r})+2\pi r^2

Factorize:

A=2\pi (\frac{432}{r} + r^2)

To minimize, we have to differentiate both sides and set A' = 0

A'=2\pi (-\frac{432}{r^2} + 2r)

Set A' = 0

0=2\pi (-\frac{432}{r^2} + 2r)

Divide through by 2\pi

0= -\frac{432}{r^2} + 2r

\frac{432}{r^2} = 2r

Cross Multiply

2r * r^2 = 432

2r^3 = 432

Divide through by 2

r^3 = 216

Take cube roots of both sides

r = \sqrt[3]{216}

r = 6

Recall that:

h = \frac{432}{r^2}

h = \frac{432}{6^2}

h = \frac{432}{36}

h = 12

Hence, the dimension that requires the least amount of material is when

Height = 12cm

Radius = 6cm

3 0
3 years ago
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